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y > 0

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GMAT Club Legend
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y > 0 [#permalink] New post 29 Apr 2018, 00:31
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Question Stats:

37% (01:04) correct 62% (00:41) wrong based on 16 sessions
y > 0

Quantity A
Quantity B
\((\frac{2}{y})^{3}\)
\((\frac{3}{y})^{2}\)


A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: y > 0 [#permalink] New post 30 Apr 2018, 05:22
D
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Re: y > 0 [#permalink] New post 01 May 2018, 05:33
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waqas123 wrote:
D

Mind sharing your hought process. It would be helpful for other students as well.
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Re: y > 0 [#permalink] New post 02 May 2018, 06:25
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After simplification, equation becomes 8/y^3 and 9/y^2.

Since y>0 so multiply both sides by y^2. You will get 8/y and 9. If y is an integer then quantity A will always be less than B. If y is a proper fraction,say 0.8, quantity A will be 10. Here comes the contradiction of first case so relationship cannot be established.
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Re: y > 0 [#permalink] New post 11 May 2018, 18:45
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y as a fraction vs ya as a whole number can change the answer options hence the answer
GMAT Club Legend
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Joined: 07 Jun 2014
Posts: 4722
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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Kudos [?]: 1630 [0], given: 390

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Re: y > 0 [#permalink] New post 13 May 2018, 12:29
Expert's post
mohan514 wrote:
y as a fraction vs ya as a whole number can change the answer options hence the answer


Correct,however it is a bit simple. While shortcuts are great time saver but use them wisely they are not very reliable unless you have a decent command of the topic.

Preferably try to solve the question specially with exponential and percentages they can be tricky.
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GMAT Club Legend
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Joined: 07 Jun 2014
Posts: 4722
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 91

Kudos [?]: 1630 [0], given: 390

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Re: y > 0 [#permalink] New post 13 May 2018, 15:33
Expert's post
Explanation

Plug in values for y. If y = 1, then Quantity A is 8 and Quantity B is 9.

In this case, Quantity B is larger, so eliminate choices (A) and (C). If \(\frac{1}{2}\), then Quantity A is 64 and Quantity B is 36; eliminate choice (B).

You are left with choice (D).
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Re: y > 0   [#permalink] 13 May 2018, 15:33
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