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y > 4

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y > 4 [#permalink] New post 07 Sep 2017, 14:22
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Question Stats:

71% (00:36) correct 28% (00:39) wrong based on 134 sessions
\(y > 4\)

Quantity A
Quantity B
\(\frac{3y+2}{5}\)
\(y\)



A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


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Question: 6
Page: 113
Difficulty: medium
[Reveal] Spoiler: OA

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Re: y > 4 [#permalink] New post 07 Sep 2017, 14:40
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Explanation

Tricky question.

The stem says that y > 4 but it does not mention the fact that it could be an integer such as 5 or a fraction such as \(\frac{6}{1.4} = 4.2\)

If you substitute 5 to A the result is 3.4 that is less than 4. OR 4.2 the result is 2.92 that is less than 4.

So, no matter what quantity B is > than quantity A

B is the answer
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Re: y > 4 [#permalink] New post 12 Sep 2017, 08:34
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Multiply both sides by 5 and then subtract 3y. You get 2 vs 2y, and since y > 4, quantity B will always be bigger
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Re: y > 4 [#permalink] New post 27 Mar 2019, 17:15
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Carcass wrote:
\(y > 4\)

Quantity A
Quantity B
\(\frac{3y+2}{5}\)
\(y\)




We can solve this question using matching operations

Given:
Quantity A: \(\frac{3y+2}{5}\)
Quantity B: \(y\)

Multiply both quantities by 5 to get:
Quantity A: \(3y+2\)
Quantity B: \(5y\)

Subtract 3y from both quantities to get:
Quantity A: \(2\)
Quantity B: \(2y\)

Divide both quantities by 2 to get:
Quantity A: \(1\)
Quantity B: \(y\)

Since we're told that y > 4, we know that Quantity B is greater.

Answer: B



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Re: y > 4 [#permalink] New post 14 Jul 2019, 02:00
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One can solve using graph
as below
both function meet at (1,1) ~ (y,f(y))
from point (1,1) f(y)=y is grater then f(y) = 3y+2 / 5

check attachment/picture
Attachments

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Untitled.png [ 15.28 KiB | Viewed 1240 times ]

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Re: y > 4 [#permalink] New post 14 Jul 2019, 02:02
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Great graph solution.

Thank you
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Re: y > 4 [#permalink] New post 17 Sep 2019, 02:16
GreenlightTestPrep wrote:
Carcass wrote:
\(y > 4\)

Quantity A
Quantity B
\(\frac{3y+2}{5}\)
\(y\)




We can solve this question using matching operations

Given:
Quantity A: \(\frac{3y+2}{5}\)
Quantity B: \(y\)

Multiply both quantities by 5 to get:
Quantity A: \(3y+2\)
Quantity B: \(5y\)

Subtract 3y from both quantities to get:
Quantity A: \(2\)
Quantity B: \(2y\)

Divide both quantities by 2 to get:
Quantity A: \(1\)
Quantity B: \(y\)

Since we're told that y > 4, we know that Quantity B is greater.

Answer: B



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Interesting approach!
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Re: y > 4 [#permalink] New post 17 Sep 2019, 05:00
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kloppismydad wrote:
Interesting approach!


Thanks! I think it's one of the most useful strategies for solving Quantitative Comparison questions.
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Re: y > 4   [#permalink] 17 Sep 2019, 05:00
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