Explanation

Tricky question.

The stem says that y > 4 but it does not mention the fact that it could be an integer such as 5 or a fraction such as \(\frac{6}{1.4} = 4.2\)

If you substitute 5 to A the result is 3.4 that is less than 4. OR 4.2 the result is 2.92 that is less than 4.

So, no matter what quantity B is > than quantity A

B is the answer
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Multiply both sides by 5 and then subtract 3y. You get 2 vs 2y, and since y > 4, quantity B will always be bigger

We can solve this question using matching operations

Given:
Quantity A: \(\frac{3y+2}{5}\)
Quantity B: \(y\)

Multiply both quantities by 5 to get:
Quantity A: \(3y+2\)
Quantity B: \(5y\)

Subtract 3y from both quantities to get:
Quantity A: \(2\)
Quantity B: \(2y\)

Divide both quantities by 2 to get:
Quantity A: \(1\)
Quantity B: \(y\)

Since we're told that y > 4, we know that Quantity B is greater.

Answer: B



RELATED VIDEO FROM MY COURSE

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One can solve using graph
as below
both function meet at (1,1) ~ (y,f(y))
from point (1,1) f(y)=y is grater then f(y) = 3y+2 / 5

check attachment/picture

Great graph solution.

Thank you
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Interesting approach!

Thanks! I think it's one of the most useful strategies for solving Quantitative Comparison questions.
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If y = 5, we get:
Quantity A: [3(5) + 2]/5
Quantity B: 5

Simplify to get:
Quantity A: 3.4
Quantity B: 5

So, Quantity B is greater (not Quantity A).
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Substitute 4.1

we get LHS = 2.86 < 4.1

ans B

Then we take y = 5

RHS --> 3(5) + 2 / 5 = 17/5 = its ~3.4 and RHS = 5

Ans B