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Expert's post 00:00

Question Stats: 87% (00:30) correct 12% (00:24) wrong based on 39 sessions
$$y=\frac{3x}{4}, x=\frac{2z}{3}$$, and $$z=20$$.

 Quantity A Quantity B y 11

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Carcass wrote:
$$y=\frac{3x}{4}, x=\frac{2z}{3}$$, and $$z=20$$.

 Quantity A Quantity B y 11

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Here,
$$x=\frac{2z}{3} = \frac{(2 * 20)}{3} =\frac{40}{3}$$

And,
$$y=\frac{3x}{4} = \frac{(3 * 40)}{(4 * 3)} = 10$$

Hence,
QTY A < QTY B
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Expert's post
Carcass wrote:
$$y=\frac{3x}{4}, x=\frac{2z}{3}$$, and $$z=20$$.

 Quantity A Quantity B y 11

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Given: $$y=\frac{3x}{4}$$

Rewrite as follows: $$y=(\frac{3}{4})x$$

Substitute: $$y=(\frac{3}{4})(\frac{2z}{3})$$

Simplify: $$y=\frac{z}{2}$$

Substitute: $$y=\frac{20}{2} = 10$$

We get:
QUANTITY A: 10
QUANTITY B: 11

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com
If you enjoy my solutions, you'll like my GRE prep course.  Re: y=3x/4, x=2z/3   [#permalink] 13 May 2020, 08:35
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