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Xyla can paint a fence in 6 hrs. Working alone, Yarba can pa

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Xyla can paint a fence in 6 hrs. Working alone, Yarba can pa [#permalink] New post 01 Oct 2017, 04:28
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Xyla can paint a fence in 6 hrs. Working alone, Yarba can paint the same fence in x hours. Working together they can complete the task in 2.1 hrs.

Quantity A
Quantity B
x
3


A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

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[Reveal] Spoiler: OA
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Re: Xyla can paint a fence in 6 hrs. Working alone, Yarba can pa [#permalink] New post 01 Oct 2017, 06:13
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Bunuel wrote:
Xyla can paint a fence in 6 hrs. Working alone, Yarba can paint the same fence in x hours. Working together they can complete the task in 2.1 hrs.

Quantity A
Quantity B
x
3



We know
time taken if Xyla and Yarba work together then total time taken is given by

\(\frac{6*x}{6+x}=2.1\)

or \(x\)= 3.2

Therefore option A
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Re: Xyla can paint a fence in 6 hrs. Working alone, Yarba can pa   [#permalink] 01 Oct 2017, 06:13
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Xyla can paint a fence in 6 hrs. Working alone, Yarba can pa

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