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Retired Moderator Joined: 07 Jun 2014
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GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
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xy2z(x2z + yz2 - xy2) vs x3y2z2 + xy3z3 - x2y4z [#permalink]
Expert's post 00:00

Question Stats: 90% (00:32) correct 9% (00:37) wrong based on 93 sessions
 Quantity A Quantity B $$xy^2z(x^2z + yz^2 - xy^2)$$ $$x^3y^2z^2 + xy^3z^3 - x^2y^4z$$

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: xy2z(x2z + yz2 - xy2) vs x3y2z2 + xy3z3 - x2y4z [#permalink]
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sandy wrote:
 Quantity A Quantity B $$xy^2z(x^2z + yz^2 - xy^2)$$ $$x^3y^2z^2 + xy^3z^3 - x^2y^4z$$

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Here;

In statement 1 : $$xy^2z(x^2z + yz^2 - xy^2)$$ = $$x^3y^2z^2 + xy^3z^3 - x^2y^4z$$ = statement 2

Hence option C
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Retired Moderator Joined: 07 Jun 2014
Posts: 4803
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
Followers: 171

Kudos [?]: 2926 , given: 394

Re: xy2z(x2z + yz2 - xy2) vs x3y2z2 + xy3z3 - x2y4z [#permalink]
Expert's post
Explanation

In Quantity A, the term xy2z on the outside of the parentheses must be multiplied by each of the three terms inside the parentheses. Then simplify the expression as much as possible.

Taking one term at a time, the first is $$xy^2z \times x^2z = x^3y^2z^2$$, because there are three factors of x, two factors of y, and two factors of z. Similarly, the second term is $$xy^2z \times yz^2 = xy^3z^3$$ and the third is $$xy^2z \times (-xy^2) = -x^2y^4z$$.

Adding these three terms together gives the distributed form of Quantity A: $$x^3y^2z^2 + xy^3z^3 - x^2y^4z$$.

This is identical to Quantity B, so the two quantities are equal.
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Sandy
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Try our free Online GRE Test Re: xy2z(x2z + yz2 - xy2) vs x3y2z2 + xy3z3 - x2y4z   [#permalink] 17 Jul 2018, 12:07
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