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xy > 0

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GMAT Club Legend
GMAT Club Legend
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Joined: 07 Jun 2014
Posts: 4749
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 93

Kudos [?]: 1651 [0], given: 396

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xy > 0 [#permalink] New post 23 Jun 2018, 12:08
Expert's post
00:00

Question Stats:

96% (00:47) correct 3% (00:55) wrong based on 26 sessions
\(xy > 0\)
Quantity A
Quantity B
\((2x - y)(x + 4y)\)
\(2x^2\) + \(8xy\) – \(4y^2\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Sandy
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Director
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Joined: 20 Apr 2016
Posts: 756
Followers: 6

Kudos [?]: 511 [0], given: 94

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Re: xy > 0 [#permalink] New post 29 Jun 2018, 05:22
sandy wrote:
\(xy > 0\)
Quantity A
Quantity B
\((2x - y)(x + 4y)\)
\(2x^2\) + \(8xy\) – \(4y^2\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


Here;
Statement 1: \((2x - y)(x + 4y)\) = \(2x^2\)+ \(8xy\) - \(xy\)– \(4y^2\) = \(2x^2\) + \(7xy\) –\(4y^2\)

Statement 2:\(2x^2\)+ \(8xy\) – \(4y^2\)
Since xy>0

Therefore Statement 1 < Statement 2
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GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 07 Jun 2014
Posts: 4749
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 93

Kudos [?]: 1651 [0], given: 396

CAT Tests
Re: xy > 0 [#permalink] New post 16 Jul 2018, 18:54
Expert's post
Explanation

the terms in Quantity A:
\((2x - y)(x + 4y) = 2x^2 + 8xy - xy - 4y^2 = 2x^2 + 7xy - 4y2\)

Since \(2x^2\) and \(-4y^2\) appear in both quantities, eliminate them.

Quantity A is now equal to 7xy and Quantity B is now equal to 8xy.

Because xy > 0, Quantity B is greater. (Don’t assume! If xy were zero, the two quantities would have been equal. If xy were negative, Quantity A would have been greater.)
_________________

Sandy
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Re: xy > 0   [#permalink] 16 Jul 2018, 18:54
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