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Retired Moderator Joined: 07 Jun 2014
Posts: 4803
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
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Kudos [?]: 3041 , given: 394

Expert's post 00:00

Question Stats: 79% (00:46) correct 20% (00:57) wrong based on 62 sessions
$$xy > 0$$
 Quantity A Quantity B $$(2x - y)(x + 4y)$$ $$2x^2$$ + $$8xy$$ – $$4y^2$$

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

_________________

Sandy
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VP Joined: 20 Apr 2016
Posts: 1302
WE: Engineering (Energy and Utilities)
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Kudos [?]: 1342 , given: 251

sandy wrote:
$$xy > 0$$
 Quantity A Quantity B $$(2x - y)(x + 4y)$$ $$2x^2$$ + $$8xy$$ – $$4y^2$$

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Here;
Statement 1: $$(2x - y)(x + 4y)$$ = $$2x^2$$+ $$8xy$$ - $$xy$$– $$4y^2$$ = $$2x^2$$ + $$7xy$$ –$$4y^2$$

Statement 2:$$2x^2$$+ $$8xy$$ – $$4y^2$$
Since xy>0

Therefore Statement 1 < Statement 2
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Retired Moderator Joined: 07 Jun 2014
Posts: 4803
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
Followers: 176

Kudos [?]: 3041 , given: 394

Expert's post
Explanation

the terms in Quantity A:
$$(2x - y)(x + 4y) = 2x^2 + 8xy - xy - 4y^2 = 2x^2 + 7xy - 4y2$$

Since $$2x^2$$ and $$-4y^2$$ appear in both quantities, eliminate them.

Quantity A is now equal to 7xy and Quantity B is now equal to 8xy.

Because xy > 0, Quantity B is greater. (Don’t assume! If xy were zero, the two quantities would have been equal. If xy were negative, Quantity A would have been greater.)
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Sandy
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Try our free Online GRE Test Re: xy > 0   [#permalink] 16 Jul 2018, 18:54
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