Carcass wrote:
xy ≠ 0
\(\frac{a}{xs}=632\) and \(\frac{a}{ys}=158\)
Quantity A |
Quantity B |
x |
y |
Here \(\frac{a}{xs} =632\)
or a = 632xs
And from 2nd equ we have
a= 158ys
Therefore we can write as -
632xs=158ys
or y/x = 4
There fore one possible way can be possible
if x=1 and y= 4 , therefore x<y
or if x = -1 and y = -4, therefore x>y
These both values are possible, since the question didnot mentioned that both x and y are positive
Hence option D
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