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# x -y+z=0 2x +y + 3z = 0 In the system of equations above, i

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x -y+z=0 2x +y + 3z = 0 In the system of equations above, i [#permalink]  18 May 2018, 15:06
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$$x - y + z=0$$

$$2x +y + 3z = 0$$

In the system of equations above, if $$z \neq 0$$, then the ratio of x to z is

(A) $$- \frac{2}{1}$$

(B) $$- \frac{4}{3}$$

(C) $$- \frac{1}{2}$$

(D) $$\frac{3}{4}$$

(E) $$\frac{4}{3}$$
[Reveal] Spoiler: OA

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Re: x -y+z=0 2x +y + 3z = 0 In the system of equations above, i [#permalink]  19 May 2018, 06:34
From the equations, x+z = y.

Replacing y in 2nd equation with this value and solving for x/z give -4/3.

Re: x -y+z=0 2x +y + 3z = 0 In the system of equations above, i   [#permalink] 19 May 2018, 06:34
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