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(–x + y)(–y + x) = x2 – y2 y2 – x2 0 –(x – y)2 (y – x)2

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CEO
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Joined: 07 Jun 2014
Posts: 3223
GRE 1: 323 Q167 V156
WE: Business Development (Energy and Utilities)
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(–x + y)(–y + x) = x2 – y2 y2 – x2 0 –(x – y)2 (y – x)2 [#permalink] New post 15 Apr 2018, 03:49
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Question Stats:

100% (00:21) correct 0% (00:00) wrong based on 1 sessions
(-x + y)(-y + x) =

A. x2 - y2
B. y^2 - x^2
C. 0
D. -(x - y)^2
E. (y - x)^2

Drill 2
Question: 7
Page: 511

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Re: (–x + y)(–y + x) = x2 – y2 y2 – x2 0 –(x – y)2 (y – x)2 [#permalink] New post 16 Apr 2018, 02:29
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expand the expression

(-x + y)(-y + x) = xy -x^2 -y^2 + xy
or, (-x + y)(-y + x) = 2xy -x^2 - y^2
or, (-x + y)(-y + x) = -(-2xy + x^2 + y^2)
The expression inside the bracket is similar to (a-b)^2 so in that format
The expression reduces to -(x - y)^2
option D
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Re: (–x + y)(–y + x) = x2 – y2 y2 – x2 0 –(x – y)2 (y – x)2   [#permalink] 16 Apr 2018, 02:29
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