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x > y, x and y are positive integers [#permalink]
22 Feb 2017, 02:23
Question Stats:
80% (01:03) correct
20% (00:38) wrong based on 5 sessions
\(x > y\), x and y are positive integers. Which of the following statements provide the necessary information to state that y is a factor of x?
1. \(\frac{x}{y} = k\); k is a positive integer
2. x is a multiple of 6 and y is a multiple of 3
3. Every prime factor of y is also a prime factor of x.
Last edited by Carcass on 05 Sep 2018, 11:02, edited 1 time in total.
Edited by Carcass




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Re: number properties [#permalink]
15 Oct 2017, 01:08
shadowcatradz wrote: x > y, x and y are positive integers. Which of the following statements provide the necessary information to state that y is a factor of x?
1. x/y = k; k is a positive integer 2. x is a multiple of 6 and y is a multiple of 3 3. Every prime factor of y is also a prime factor of x. 1. This is true only for even number, but x and y can be odd too. 2. but y cannot be multiple of 3 and then factor of x for all cases e.g. X = 54 and Y = 15. 3. This is possible e.g. if we factor out a multiple of 6 say 18 = 2*3*3 and 9 = 3*3 , so factor of 9 included in 18. so option 3 is the answer.



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Re: number properties [#permalink]
05 Sep 2018, 11:00
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LethalMonkey wrote: shadowcatradz wrote: x > y, x and y are positive integers. Which of the following statements provide the necessary information to state that y is a factor of x?
1. x/y = k; k is a positive integer 2. x is a multiple of 6 and y is a multiple of 3 3. Every prime factor of y is also a prime factor of x. 1. This is true only for even number, but x and y can be odd too. 2. but y cannot be multiple of 3 and then factor of x for all cases e.g. X = 54 and Y = 15. 3. This is possible e.g. if we factor out a multiple of 6 say 18 = 2*3*3 and 9 = 3*3 , so factor of 9 included in 18. so option 3 is the answer. I think you got the first option wrong my friend. What the question wants to know is if x= a* y (where a is any number) they are asking if x is a factor of Y. Now option one states that x/y=K which if you make simpler would look like x=Y*K which means both K and Y are factors of X.



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Re: x > y, x and y are positive integers [#permalink]
05 Sep 2018, 11:05



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Re: number properties [#permalink]
11 Jun 2019, 06:44
abhinavk48 wrote: LethalMonkey wrote: shadowcatradz wrote: x > y, x and y are positive integers. Which of the following statements provide the necessary information to state that y is a factor of x?
1. x/y = k; k is a positive integer 2. x is a multiple of 6 and y is a multiple of 3 3. Every prime factor of y is also a prime factor of x. 1. This is true only for even number, but x and y can be odd too. 2. but y cannot be multiple of 3 and then factor of x for all cases e.g. X = 54 and Y = 15. 3. This is possible e.g. if we factor out a multiple of 6 say 18 = 2*3*3 and 9 = 3*3 , so factor of 9 included in 18. so option 3 is the answer. I think you got the first option wrong my friend. What the question wants to know is if x= a* y (where a is any number) they are asking if x is a factor of Y. Now option one states that x/y=K which if you make simpler would look like x=Y*K which means both K and Y are factors of X.  Regarding the option 1: X/y=k where K is a positive INTEGER, We can conclude that x is divisible by y, because the result is an INTEGER (K) , no matter whether x and y are both even or both odd. So, option 1 is correct, right ?
Last edited by jelal123 on 11 Jun 2019, 07:57, edited 1 time in total.



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Re: number properties [#permalink]
11 Jun 2019, 06:56
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jelal123 wrote:  Regarding the option 1: X/y=k where K is a positive INTEGER, We can conclude that x is divisible by x, because the result is an INTEGER (K) , no matter whether x and y are both even or both odd. So, option 1 is correct, right ? That's correct, if x and y are positive integers, and x/y = some positive integer, then y is a factor of x Cheers, Brent
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Re: x > y, x and y are positive integers [#permalink]
01 Jul 2019, 10:29
Online option i is correct




Re: x > y, x and y are positive integers
[#permalink]
01 Jul 2019, 10:29





