Oct 31 08:00 PM PDT  09:00 PM PDT Join timely conversations and get muchneeded information about your educational future in our free event series. The sessions will focus on a variety of topics, from going to college in a pandemic to racial inequality in education. Nov 02 08:00 PM MST  09:00 PM MST Free test questions, video lessons, and more. Nov 05 08:00 PM MST  09:00 PM MST Learn how to evaluate your profile, skills, and experiences to determine if, when, and where you should apply to graduate school.
Author 
Message 
TAGS:


Founder
Joined: 18 Apr 2015
Posts: 13664
Followers: 304
Kudos [?]:
3522
[0], given: 12599

x, y, and z are consecutive integers, where x < y < z. Whic [#permalink]
12 Aug 2017, 09:59
Question Stats:
56% (01:23) correct
43% (00:59) wrong based on 93 sessions
x, y, and z are consecutive integers, where x < y < z. Which of the following must be divisible by 3 ? Indicate all that apply. A) xyz B) (x + 1)yz C) (x + 2)yz D) (x + 3)yz E) (x + 1)(y + 1)(z + 1) F) (x + 1)(y + 2)(z + 3)
_________________
Need Practice? 20 Free GRE Quant Tests available for free with 20 Kudos GRE Prep Club Members of the Month: Each member of the month will get three months free access of GRE Prep Club tests. Eddie Van Halen  Beat it R.I.P.




Intern
Joined: 14 Jun 2018
Posts: 36
Followers: 0
Kudos [?]:
9
[0], given: 100

Re: x, y, and z are consecutive integers, where x < y < z. Whic [#permalink]
08 Jul 2018, 06:36
Carcass wrote: x, y, and z are consecutive integers, where x < y < z. Which of the following must be divisible by 3 ? Indicate all that apply. ❑ xyz ❑ (x + 1)yz ❑ (x + 2)yz ❑ (x + 3)yz ❑ (x + 1)(y + 1)(z + 1) ❑ (x + 1)(y + 2)(z + 3) Any explanation please, especially for the last one (F) and (D)?



Founder
Joined: 18 Apr 2015
Posts: 13664
Followers: 304
Kudos [?]:
3522
[2]
, given: 12599

Re: x, y, and z are consecutive integers, where x < y < z. Whic [#permalink]
08 Jul 2018, 10:30
2
This post received KUDOS
The stem is pretty straight: 3 consecutive numbers and integers. Pick 1,2,3 D) \((x + 3)yz\) \(= 4*6=24\) divisible by 3 F) \((x + 1)(y + 2)(z + 3) = 2*4*6= 48\) divisible by 3 Each number above has a number divisible by 3 inside. So they must be divisible by 3 Hope this helps PS: more often than not is useful picking number strategy instead to think theoretically, especially when you are not at that level. Regards
_________________
Need Practice? 20 Free GRE Quant Tests available for free with 20 Kudos GRE Prep Club Members of the Month: Each member of the month will get three months free access of GRE Prep Club tests. Eddie Van Halen  Beat it R.I.P.



Intern
Joined: 07 Jul 2018
Posts: 9
Followers: 0
Kudos [?]:
5
[0], given: 1

Re: x, y, and z are consecutive integers, where x < y < z. Whic [#permalink]
13 Jul 2018, 17:32
Why not B & C?



Intern
Joined: 14 Jun 2018
Posts: 36
Followers: 0
Kudos [?]:
9
[1]
, given: 100

Re: x, y, and z are consecutive integers, where x < y < z. Whic [#permalink]
13 Jul 2018, 22:47
1
This post received KUDOS
Akash03jain wrote: Why not B & C? Thanks Carcass. Back to your question, the reason simply because 3,4,5 in B are 4 * 4 * 5 does not have 3 prime factor, so it's not divisible. Same with C.



Manager
Joined: 18 Jun 2019
Posts: 122
Followers: 1
Kudos [?]:
28
[0], given: 62

Re: x, y, and z are consecutive integers, where x < y < z. Whic [#permalink]
06 Sep 2019, 08:00
Why are we not considering the possibility that the integers are negative?
what if we pick x=3, y=2, z=1? Then only A is satisfied...



GRE Instructor
Joined: 10 Apr 2015
Posts: 3871
Followers: 158
Kudos [?]:
4639
[3]
, given: 70

Re: x, y, and z are consecutive integers, where x < y < z. Whic [#permalink]
06 Sep 2019, 10:04
3
This post received KUDOS
bellavarghese wrote: Why are we not considering the possibility that the integers are negative?
what if we pick x=3, y=2, z=1? Then only A is satisfied... If x=3, y=2, z=1, then A, D, E and F are divisible by 3. KEY CONCEPT: O is divisible by 3 (but I've never seen an OFFICIAL GRE question that tests this) Cheers, Brent
_________________
Brent Hanneson – Creator of greenlighttestprep.com If you enjoy my solutions, you'll like my GRE prep course.
Sign up for GRE Question of the Day emails



Manager
Joined: 18 Jun 2019
Posts: 122
Followers: 1
Kudos [?]:
28
[0], given: 62

Re: x, y, and z are consecutive integers, where x < y < z. Whic [#permalink]
06 Sep 2019, 10:54
GreenlightTestPrep wrote: bellavarghese wrote: Why are we not considering the possibility that the integers are negative?
what if we pick x=3, y=2, z=1? Then only A is satisfied... If x=3, y=2, z=1, then A, D, E and F are divisible by 3. KEY CONCEPT: O is divisible by 3 (but I've never seen an OFFICIAL GRE question that tests this) Cheers, Brent oh. That's new info for me. Thanks!



Intern
Joined: 23 Oct 2019
Posts: 4
Followers: 0
Kudos [?]:
2
[0], given: 2

Re: x, y, and z are consecutive integers, where x < y < z. Whic [#permalink]
16 Apr 2020, 00:24
If we select 1,2 and 3 for x,y and z respectively, B and C can eval to true
B) (x + 1)yz = y * y * z ( since z is 3, any multiple of 3 is divisible by 3 )
C) (x + 2)yz = z * y * z ( following the same logic )
Can anyone explain why this is not possible?



Founder
Joined: 18 Apr 2015
Posts: 13664
Followers: 304
Kudos [?]:
3522
[0], given: 12599

Re: x, y, and z are consecutive integers, where x < y < z. Whic [#permalink]
16 Apr 2020, 01:39
Now, if either y or z is a multiple of 3, then the expressions in choices B and C will also be divisible by 3, but you do not know for certain which of x, y, and z is the multiple of B and C are not MUST be true
_________________
Need Practice? 20 Free GRE Quant Tests available for free with 20 Kudos GRE Prep Club Members of the Month: Each member of the month will get three months free access of GRE Prep Club tests. Eddie Van Halen  Beat it R.I.P.




Re: x, y, and z are consecutive integers, where x < y < z. Whic
[#permalink]
16 Apr 2020, 01:39





