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|x| > |y| and x + y > 0

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Moderator
Joined: 18 Apr 2015
Posts: 4906
Followers: 74

Kudos [?]: 976 [0], given: 4497

|x| > |y| and x + y > 0 [#permalink]  08 Aug 2018, 16:42
Expert's post
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Question Stats:

60% (00:57) correct 39% (00:55) wrong based on 28 sessions
$$|x| > |y|$$ and $$x + y > 0$$

 Quantity A Quantity B y x

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E
[Reveal] Spoiler: OA

_________________
Manager
Joined: 06 Jun 2018
Posts: 94
Followers: 0

Kudos [?]: 55 [1] , given: 0

Re: |x| > |y| and x + y > 0 [#permalink]  09 Aug 2018, 15:05
1
KUDOS
Carcass wrote:
$$|x| > |y|$$ and $$x + y > 0$$

 Quantity A Quantity B y x

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E

Given

$$|x| > |y|$$

$$x^2 > y^2$$................we can do it safely as both x and y are in absolute value sign.

$$x^2 - y^2 >0$$

(x + y) (x -Y) > 0

We know x + y> 0 , thus x - y> 0

So, x - y >0 or x>y.

Intern
Joined: 10 Oct 2017
Posts: 10
Followers: 0

Kudos [?]: 3 [0], given: 0

Re: |x| > |y| and x + y > 0 [#permalink]  24 Sep 2018, 19:48
kaziselim wrote:
Carcass wrote:
$$|x| > |y|$$ and $$x + y > 0$$

 Quantity A Quantity B y x

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E

Given

$$|x| > |y|$$

$$x^2 > y^2$$................we can do it safely as both x and y are in absolute value sign.

$$x^2 - y^2 >0$$

(x + y) (x -Y) > 0

We know x + y> 0 , thus x - y> 0

So, x - y >0 or x>y.

thats a nice approach
Re: |x| > |y| and x + y > 0   [#permalink] 24 Sep 2018, 19:48
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