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x > y > 0

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x > y > 0 [#permalink] New post 16 Apr 2018, 15:32
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Question Stats:

100% (00:23) correct 0% (00:00) wrong based on 5 sessions
\(x > y > 0\)

Quantity A
Quantity B
\(x - y\)
\(\frac{x}{3} + \frac{y}{3}\)


A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
[Reveal] Spoiler: OA

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Re: x > y > 0 [#permalink] New post 18 Apr 2018, 02:05
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simplify the given quantities

\(x -y\) \(?\) \(x+y/3\)
\(3x - 3y ? x + y\)
subtracting x from both sides
\(2x - 3y ? y\)
subtracting y from both sides
\(2x -4y ? 0\)
adding 4y to both sides
\(2x ? 4y\)
Dividing both sides by \(2\)
\(x ? 2y\)
we know that \(x > y\) but we do not know by how much so
it could be the case that \(x =4\) and \(y =2\) so both quantities are equal or
\(x = 100\) and \(y = 10\) and as such \(2y =20\)
A>B
Therefore option D
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Re: x > y > 0   [#permalink] 18 Apr 2018, 02:05
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