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x > y > 0

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Joined: 18 Apr 2015
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Kudos [?]: 1156 [0], given: 5481

x > y > 0 [#permalink]  16 Apr 2018, 15:32
Expert's post
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Question Stats:

69% (00:37) correct 30% (01:37) wrong based on 13 sessions

$$x > y > 0$$

 Quantity A Quantity B $$x - y$$ $$\frac{x}{3} + \frac{y}{3}$$

A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
[Reveal] Spoiler: OA

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Joined: 07 Jan 2018
Posts: 604
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Kudos [?]: 546 [1] , given: 88

Re: x > y > 0 [#permalink]  18 Apr 2018, 02:05
1
KUDOS
simplify the given quantities

$$x -y$$ $$?$$ $$x+y/3$$
$$3x - 3y ? x + y$$
subtracting x from both sides
$$2x - 3y ? y$$
subtracting y from both sides
$$2x -4y ? 0$$
$$2x ? 4y$$
Dividing both sides by $$2$$
$$x ? 2y$$
we know that $$x > y$$ but we do not know by how much so
it could be the case that $$x =4$$ and $$y =2$$ so both quantities are equal or
$$x = 100$$ and $$y = 10$$ and as such $$2y =20$$
A>B
Therefore option D
_________________

This is my response to the question and may be incorrect. Feel free to rectify any mistakes

Re: x > y > 0   [#permalink] 18 Apr 2018, 02:05
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