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# x > y

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x > y [#permalink]  04 Mar 2017, 03:06
Expert's post
00:00

Question Stats:

80% (00:34) correct 20% (01:02) wrong based on 55 sessions

$$x > y$$

 Quantity A Quantity B $$\frac{1}{3}x$$ $$\frac{1}{2}y$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Joined: 07 Jun 2014
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GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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Re: x > y [#permalink]  07 Mar 2017, 15:26
Expert's post
Explanation

The best way to solve this to plug values of x and y such that $$x > y$$.

x = 3 and y =2

Quantity A: 1

Quantity B: 1

x = 12 and y =4

Quantity A: 4

Quantity B: 2

Quantity A is greater.

Thus a relationship cannot be determined. Hence option D is correct.
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Sandy
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Manager
Joined: 27 Sep 2017
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Re: x > y [#permalink]  27 Mar 2018, 23:35
sandy wrote:
Explanation

The best way to solve this to plug values of x and y such that $$x > y$$.

x = 3 and y =2

Quantity A: 1

Quantity B: 1

x = 12 and y =4

Quantity A: 4

Quantity B: 2

Quantity A is greater.

Thus a relationship cannot be determined. Hence option D is correct.

there is some problem with the stem. are x and y in the denominator or outside the denominator ? if insdie the ans should be B.
GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4857
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 105

Kudos [?]: 1783 [0], given: 397

Re: x > y [#permalink]  27 Mar 2018, 23:47
Expert's post
Fixed!
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Sandy
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Re: x > y [#permalink]  28 Mar 2018, 01:55
Expert's post
The quantities, if I remember well, were wrote in the right way. Now, they are in the right and definitive way.

Moreover, the two quantities were not wrong actually because writing $$\frac{1}{3}x$$ or writing $$\frac{x}{3}$$ is exactly the same. As such, the question was still valid.

Aside note: the explanation above considers only integers but when a stem says : x>y you do not know whether they are integers or also fractions. We should consider both to tackle the question.

Regards
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Re: x > y   [#permalink] 28 Mar 2018, 01:55
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