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TAGS: Active Member  Joined: 07 Jan 2018
Posts: 694
Followers: 11

Kudos [?]: 778  , given: 88

x - y > 0 and x > 1 and √(-)=√x [#permalink]
1
KUDOS 00:00

Question Stats: 65% (01:09) correct 34% (01:14) wrong based on 23 sessions
$$x - y > 0$$ and $$x > 1$$ and $$\sqrt{(x-y)}=\sqrt{x}-1$$

 Quantity A Quantity B $$Y$$ $$2 \sqrt{x}-1$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA GRE Instructor Joined: 10 Apr 2015
Posts: 3876
Followers: 159

Kudos [?]: 4683  , given: 70

Re: x - y > 0 and x > 1 and √(-)=√−1 [#permalink]
1
KUDOS
Expert's post
amorphous wrote:
$$x - y > 0$$ and $$x > 1$$ and $$\sqrt{(x-y)}=\sqrt{-1}$$

 Quantity A Quantity B $$Y$$ $$2 \sqrt{-1}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

I think this question is missing something.
As it stands, we're told that x - y > 0. In other words, x - y is POSITIVE

Then we're told that $$\sqrt{(x-y)}=\sqrt{-1}$$
This means x - y = -1
However, we earlier learned that x - y is POSITIVE

Cheers,
Brent
_________________

Brent Hanneson – Creator of greenlighttestprep.com
If you enjoy my solutions, you'll like my GRE prep course. Active Member  Joined: 07 Jan 2018
Posts: 694
Followers: 11

Kudos [?]: 778 , given: 88

Re: x - y > 0 and x > 1 and √(-)=√−1 [#permalink]
GreenlightTestPrep wrote:
amorphous wrote:
$$x - y > 0$$ and $$x > 1$$ and $$\sqrt{(x-y)}=\sqrt{-1}$$

 Quantity A Quantity B $$Y$$ $$2 \sqrt{-1}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

I think this question is missing something.
As it stands, we're told that x - y > 0. In other words, x - y is POSITIVE

Then we're told that $$\sqrt{(x-y)}=\sqrt{-1}$$
This means x - y = -1
However, we earlier learned that x - y is POSITIVE

Cheers,
Brent

yes the question was incomplete, I have changed it.
Supreme Moderator
Joined: 01 Nov 2017
Posts: 371
Followers: 12

Kudos [?]: 181 , given: 4

Re: x - y > 0 and x > 1 and √(-)=√x [#permalink]
Expert's post
amorphous wrote:
$$x - y > 0$$ and $$x > 1$$ and $$\sqrt{(x-y)}=\sqrt{x}-1$$

 Quantity A Quantity B $$Y$$ $$2 \sqrt{x}-1$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

x-y>0 ; X>1 ; $$\sqrt{(x-y)}=\sqrt{x}-1$$

Let us square $$\sqrt{(x-y)}=\sqrt{x}-1$$..
$$\sqrt{(x-y)}^2=(\sqrt{x}-1)^2........ x-y=x+1-2√x....y=2√x-1.....A=B$$

C
_________________

Some useful Theory.
1. Arithmetic and Geometric progressions : https://greprepclub.com/forum/progressions-arithmetic-geometric-and-harmonic-11574.html#p27048
2. Effect of Arithmetic Operations on fraction : https://greprepclub.com/forum/effects-of-arithmetic-operations-on-fractions-11573.html?sid=d570445335a783891cd4d48a17db9825
3. Remainders : https://greprepclub.com/forum/remainders-what-you-should-know-11524.html
4. Number properties : https://greprepclub.com/forum/number-property-all-you-require-11518.html
5. Absolute Modulus and Inequalities : https://greprepclub.com/forum/absolute-modulus-a-better-understanding-11281.html Re: x - y > 0 and x > 1 and √(-)=√x   [#permalink] 21 Oct 2018, 01:30
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