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x - y > 0 and x > 1 and √(-)=√x
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16 Aug 2018, 09:03
16 Aug 2018, 09:03
1
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Question Stats:
64% (01:08) correct
36% (01:15) wrong based on 25 sessions
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\(x - y > 0\) and \(x > 1\) and \(\sqrt{(x-y)}=\sqrt{x}-1\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(Y\) |
\(2 \sqrt{x}-1\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: x - y > 0 and x > 1 and √(-)=√−1
[#permalink]
17 Aug 2018, 06:48
17 Aug 2018, 06:48
1
Expert Reply
amorphous wrote:
\(x - y > 0\) and \(x > 1\) and \(\sqrt{(x-y)}=\sqrt{-1}\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(Y\) |
\(2 \sqrt{-1}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
I think this question is missing something.
As it stands, we're told that x - y > 0. In other words, x - y is POSITIVE
Then we're told that \(\sqrt{(x-y)}=\sqrt{-1}\)
This means x - y = -1
However, we earlier learned that x - y is POSITIVE
Cheers,
Brent
_________________
Re: x - y > 0 and x > 1 and √(-)=√−1
[#permalink]
02 Sep 2018, 20:49
02 Sep 2018, 20:49
GreenlightTestPrep wrote:
amorphous wrote:
\(x - y > 0\) and \(x > 1\) and \(\sqrt{(x-y)}=\sqrt{-1}\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(Y\) |
\(2 \sqrt{-1}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
I think this question is missing something.
As it stands, we're told that x - y > 0. In other words, x - y is POSITIVE
Then we're told that \(\sqrt{(x-y)}=\sqrt{-1}\)
This means x - y = -1
However, we earlier learned that x - y is POSITIVE
Cheers,
Brent
yes the question was incomplete, I have changed it.
Re: x - y > 0 and x > 1 and √(-)=√x
[#permalink]
21 Oct 2018, 01:30
21 Oct 2018, 01:30
Expert Reply
amorphous wrote:
\(x - y > 0\) and \(x > 1\) and \(\sqrt{(x-y)}=\sqrt{x}-1\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(Y\) |
\(2 \sqrt{x}-1\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
x-y>0 ; X>1 ; \(\sqrt{(x-y)}=\sqrt{x}-1\)
Let us square \(\sqrt{(x-y)}=\sqrt{x}-1\)..
\(\sqrt{(x-y)}^2=(\sqrt{x}-1)^2........ x-y=x+1-2√x....y=2√x-1.....A=B\)
C
_________________
Some useful Theory.
1. Arithmetic and Geometric progressions : https://greprepclub.com/forum/progressions-arithmetic-geometric-and-harmonic-11574.html#p27048
2. Effect of Arithmetic Operations on fraction : https://greprepclub.com/forum/effects-of-arithmetic-operations-on-fractions-11573.html?sid=d570445335a783891cd4d48a17db9825
3. Remainders : https://greprepclub.com/forum/remainders-what-you-should-know-11524.html
4. Number properties : https://greprepclub.com/forum/number-property-all-you-require-11518.html
5. Absolute Modulus and Inequalities : https://greprepclub.com/forum/absolute-modulus-a-better-understanding-11281.html
1. Arithmetic and Geometric progressions : https://greprepclub.com/forum/progressions-arithmetic-geometric-and-harmonic-11574.html#p27048
2. Effect of Arithmetic Operations on fraction : https://greprepclub.com/forum/effects-of-arithmetic-operations-on-fractions-11573.html?sid=d570445335a783891cd4d48a17db9825
3. Remainders : https://greprepclub.com/forum/remainders-what-you-should-know-11524.html
4. Number properties : https://greprepclub.com/forum/number-property-all-you-require-11518.html
5. Absolute Modulus and Inequalities : https://greprepclub.com/forum/absolute-modulus-a-better-understanding-11281.html
gmatclubot
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