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x,x2,xy,xy-1,x4,x6

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x,x2,xy,xy-1,x4,x6 [#permalink] New post 22 Nov 2017, 19:00
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Question Stats:

66% (00:42) correct 33% (01:25) wrong based on 3 sessions
\(x\),\(x_{2}\),\(x_{y}\),\(x_{y-1}\),\(x_{4}\),\(x_{6}\)

Quantity A
Quantity B
The mode of the numbers above when y = 4
The median of the numbers above when y =5


A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.

Drill 2
Question: 1
Page: 524
[Reveal] Spoiler: OA

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Re: x,x2,xy,xy-1,x4,x6 [#permalink] New post 23 Nov 2017, 05:46
Can someone explain this question please?
GMAT Club Legend
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Joined: 07 Jun 2014
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Re: x,x2,xy,xy-1,x4,x6 [#permalink] New post 26 Nov 2017, 17:06
Expert's post
Explanation

In Quantity A, if y = 4, then the numbers (arranged in increasing order) become \(x, x_{2}, x_{3}, x_{4}, x_{4}, x_{6}\); the mode is \(x_{2}\).

In Quantity B, if y = 5, then the numbers become \(x, x_{2}, x_{4}, x_{4}, x_{5}, x_{6}\).

Usually, you’d need to take the average of the middle two numbers to find the median because there is an even number of values, but in this case they’re both \(x_{4}\). The median, then, is \(x_{4}\), so the quantities are equal.

Because x > 1, you don’t have to worry about special cases such as 0, 1, negatives, or fractions, and the correct answer is choice (C).
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Sandy
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GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 07 Jun 2014
Posts: 4704
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 90

Kudos [?]: 1596 [0], given: 373

CAT Tests
Re: x,x2,xy,xy-1,x4,x6 [#permalink] New post 10 Dec 2017, 17:17
Expert's post
Explanation

In Quantity A, if y = 4, then the numbers (arranged in increasing order) become \(x, x_2, x_3, x_4, x_4, x_6\); the mode is \(x_4\).


In Quantity B, if y = 5, then the numbers become \(x, x_2, x_3, x_4, x_4, x_6\). Usually, you’d need to take the average of the middle two numbers to find the median because there is an even number of values, but in this case they’re both \(x_4\).

The median, then, is \(x_4\), so the quantities are equal. Because x > 1, you don’t have to worry about special cases such as 0, 1, negatives, or fractions, and the correct answer is choice C.
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Re: x,x2,xy,xy-1,x4,x6 [#permalink] New post 14 Dec 2017, 12:26
How do you know that x > 1. And what does the subscript mean?
Re: x,x2,xy,xy-1,x4,x6   [#permalink] 14 Dec 2017, 12:26
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