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# x,x2,xy,xy-1,x4,x6

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GMAT Club Legend
Joined: 07 Jun 2014
Posts: 4704
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 90

Kudos [?]: 1596 [1] , given: 373

x,x2,xy,xy-1,x4,x6 [#permalink]  22 Nov 2017, 19:00
1
KUDOS
Expert's post
00:00

Question Stats:

66% (00:42) correct 33% (01:25) wrong based on 3 sessions
$$x$$,$$x_{2}$$,$$x_{y}$$,$$x_{y-1}$$,$$x_{4}$$,$$x_{6}$$

 Quantity A Quantity B The mode of the numbers above when y = 4 The median of the numbers above when y =5

A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.

Drill 2
Question: 1
Page: 524
[Reveal] Spoiler: OA

_________________

Sandy
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Intern
Joined: 18 Nov 2017
Posts: 1
Followers: 0

Kudos [?]: 0 [0], given: 0

Re: x,x2,xy,xy-1,x4,x6 [#permalink]  23 Nov 2017, 05:46
Can someone explain this question please?
GMAT Club Legend
Joined: 07 Jun 2014
Posts: 4704
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 90

Kudos [?]: 1596 [0], given: 373

Re: x,x2,xy,xy-1,x4,x6 [#permalink]  26 Nov 2017, 17:06
Expert's post
Explanation

In Quantity A, if y = 4, then the numbers (arranged in increasing order) become $$x, x_{2}, x_{3}, x_{4}, x_{4}, x_{6}$$; the mode is $$x_{2}$$.

In Quantity B, if y = 5, then the numbers become $$x, x_{2}, x_{4}, x_{4}, x_{5}, x_{6}$$.

Usually, you’d need to take the average of the middle two numbers to find the median because there is an even number of values, but in this case they’re both $$x_{4}$$. The median, then, is $$x_{4}$$, so the quantities are equal.

Because x > 1, you don’t have to worry about special cases such as 0, 1, negatives, or fractions, and the correct answer is choice (C).
_________________

Sandy
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GMAT Club Legend
Joined: 07 Jun 2014
Posts: 4704
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 90

Kudos [?]: 1596 [0], given: 373

Re: x,x2,xy,xy-1,x4,x6 [#permalink]  10 Dec 2017, 17:17
Expert's post
Explanation

In Quantity A, if y = 4, then the numbers (arranged in increasing order) become $$x, x_2, x_3, x_4, x_4, x_6$$; the mode is $$x_4$$.

In Quantity B, if y = 5, then the numbers become $$x, x_2, x_3, x_4, x_4, x_6$$. Usually, you’d need to take the average of the middle two numbers to find the median because there is an even number of values, but in this case they’re both $$x_4$$.

The median, then, is $$x_4$$, so the quantities are equal. Because x > 1, you don’t have to worry about special cases such as 0, 1, negatives, or fractions, and the correct answer is choice C.
_________________

Sandy
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Intern
Joined: 26 Aug 2017
Posts: 31
Followers: 0

Kudos [?]: 17 [0], given: 7

Re: x,x2,xy,xy-1,x4,x6 [#permalink]  14 Dec 2017, 12:26
How do you know that x > 1. And what does the subscript mean?
Re: x,x2,xy,xy-1,x4,x6   [#permalink] 14 Dec 2017, 12:26
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