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X melts at a higher temperature than P melts. Y melts at a l

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X melts at a higher temperature than P melts. Y melts at a l [#permalink] New post 02 Mar 2020, 11:46
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46% (01:41) correct 53% (01:50) wrong based on 13 sessions
X melts at a higher temperature than P melts. Y melts at a lower temperature than P melts, but at a higher temperature than Q melts.

If the statements above are true, it can be concluded with certainty that S melts at a higher temperature than Y melts if one knows in addition that

(A) Q and P melt at a higher temperature than Smelts
(B) X melts at a higher temperature than Smelts
(C) P melts at a lower temperature than Smelts
(D) Q melts at the same temperature that Smelts
(E) S melts at a higher temperature than Q melts


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Re: X melts at a higher temperature than P melts. Y melts at a l [#permalink] New post 25 Mar 2020, 06:15
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We are given X>P, Y<P, and Y>Q.

Now for S>Y it can be that S>P since Y<P.

C states P<S, which is the same as S>P.
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Re: X melts at a higher temperature than P melts. Y melts at a l [#permalink] New post 26 Mar 2020, 05:19
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X>P>Y>Q
S>Y>Q
But we don't know S is higher or lower than X and P
So S>Q is the answer
E
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Re: X melts at a higher temperature than P melts. Y melts at a l [#permalink] New post 28 Mar 2020, 15:49

pprakash786 wrote:
We are given X>P, Y<P, and Y>Q.

Now for S>Y it can be that S>P since Y<P.

C states P<S, which is the same as S>P.

don't you think that its gonna b option E? we are confident that S>Q?
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Re: X melts at a higher temperature than P melts. Y melts at a l [#permalink] New post 30 Mar 2020, 01:44
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asmasattar00 wrote:

pprakash786 wrote:
We are given X>P, Y<P, and Y>Q.

Now for S>Y it can be that S>P since Y<P.

C states P<S, which is the same as S>P.

don't you think that its gonna b option E? we are confident that S>Q?


How can you state that?
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Re: X melts at a higher temperature than P melts. Y melts at a l [#permalink] New post 30 Mar 2020, 14:04
theBrahmaTiger wrote:
asmasattar00 wrote:

pprakash786 wrote:
We are given X>P, Y<P, and Y>Q.

Now for S>Y it can be that S>P since Y<P.

C states P<S, which is the same as S>P.

don't you think that its gonna b option E? we are confident that S>Q?


How can you state that?


option C can be a possibility, means S can be and can not be greater than P ,
Now look at question statement that ''Y melts at a higher temperature than Q melts , and S melts at a higher temperature than Y melts'' it means S>Y>Q, in that way we are confident that S>Q (option E)
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Re: X melts at a higher temperature than P melts. Y melts at a l [#permalink] New post 30 Mar 2020, 20:04
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asmasattar00 wrote:
theBrahmaTiger wrote:
asmasattar00 wrote:


don't you think that its gonna b option E? we are confident that S>Q?


How can you state that?


option C can be a possibility, means S can be and can not be greater than P ,
Now look at question statement that ''Y melts at a higher temperature than Q melts , and S melts at a higher temperature than Y melts'' it means S>Y>Q, in that way we are confident that S>Q (option E)



Its right, considering how you framed the statements. However, the framing is not as per the passage nor the question stem.

I believe your framing is based on the below (please correct if I am wrong):
You understood the passage correctly hence, Y > Q.
You took the conclusion as S > Y > Q (which is also fine)
Now you are looking at it from an inference question perspective i.e. based on the passage and the conclusion, which of the below options can be inferred.
Hence, came up with E i.e. S > Q can be inferred.


However, we are given the below:

Passage: X > P > Y > Q
Question stem states: in order for us to conclude S > Y with certainty, what additional information do I need ?
Options indicate these additional information.
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Re: X melts at a higher temperature than P melts. Y melts at a l [#permalink] New post 31 Mar 2020, 12:28
now I got it!
thank you sooo much for the productive explanation :0
Re: X melts at a higher temperature than P melts. Y melts at a l   [#permalink] 31 Mar 2020, 12:28
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