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x is an integer.

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x is an integer. [#permalink] New post 15 Sep 2017, 08:21
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Re: x is an integer. [#permalink] New post 28 Sep 2017, 08:19
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Here we have that quantity A is equal to \((-1)^{2x}+(-1)^{3x}+(-1)^{4x}\), while column B is equal to \((-1)^x+(-1)^{2x}+(-1)^{3x}+(-1)^{4x}\).
Then if we subtract the equal quantities from both sides we have to compare \(1\) and \((-1)^x\). Since we just know that x is an integer, which column is greater should depend on x being even or odd.

So, why the answer is B?
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Re: x is an integer. [#permalink] New post 28 Sep 2017, 08:38
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IlCreatore wrote:
Here we have that quantity A is equal to \((-1)^{2x}+(-1)^{3x}+(-1)^{4x}\), while column B is equal to \((-1)^x+(-1)^{2x}+(-1)^{3x}+(-1)^{4x}\).
Then if we subtract the equal quantities from both sides we have to compare \(1\) and \((-1)^x\). Since we just know that x is an integer, which column is greater should depend on x being even or odd.

So, why the answer is B?


I think you have misinterpret the ques

QTy A is

\((-1)^{x^2}+(-1)^{x^3}+(-1)^{x^4}\)

In this even if x= odd or x= even then QTY B is always greater
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Director
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Re: x is an integer. [#permalink] New post 29 Sep 2017, 04:19
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pranab01 wrote:
IlCreatore wrote:
Here we have that quantity A is equal to \((-1)^{2x}+(-1)^{3x}+(-1)^{4x}\), while column B is equal to \((-1)^x+(-1)^{2x}+(-1)^{3x}+(-1)^{4x}\).
Then if we subtract the equal quantities from both sides we have to compare \(1\) and \((-1)^x\). Since we just know that x is an integer, which column is greater should depend on x being even or odd.

So, why the answer is B?


I think you have misinterpret the ques

QTy A is

\((-1)^{x^2}+(-1)^{x^3}+(-1)^{x^3}\)

In this even if x= odd or x= even then QTY B is always greater


I hope they will be more properly written in the real test! Thanks!
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Re: x is an integer. [#permalink] New post 05 Nov 2017, 06:43
pranab01 wrote:
IlCreatore wrote:
Here we have that quantity A is equal to \((-1)^{2x}+(-1)^{3x}+(-1)^{4x}\), while column B is equal to \((-1)^x+(-1)^{2x}+(-1)^{3x}+(-1)^{4x}\).
Then if we subtract the equal quantities from both sides we have to compare \(1\) and \((-1)^x\). Since we just know that x is an integer, which column is greater should depend on x being even or odd.

So, why the answer is B?


I think you have misinterpret the ques

QTy A is

\((-1)^{x^2}+(-1)^{x^3}+(-1)^{x^4}\)

In this even if x= odd or x= even then QTY B is always greater



WHY?
Founder
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Re: x is an integer. [#permalink] New post 05 Nov 2017, 11:35
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Re: x is an integer. [#permalink] New post 05 Nov 2017, 17:10
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Carcass wrote:
Edited the first quantity in the orifinal post.

Thank you Guys.

Regards


the second one is also misleading since there is no addition mark b/t the middle
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Re: x is an integer. [#permalink] New post 05 Nov 2017, 22:19
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Re: x is an integer. [#permalink] New post 14 Nov 2017, 18:58
i think answer is D
if we consider value of x=2 then a will be 3 and will be 4

if we consider x=3 then A will be -3 and B will be 0
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Re: x is an integer. [#permalink] New post 26 Aug 2018, 00:07
Carcass wrote:



x is an integer.

Quantity A
Quantity B
\((-1)^{x^2}+(-1)^{x^3}+(-1)^{x^4}\)
\((-1)^x + (-1)^{2x} + (-1)^{3x} + (-1)^{4x}\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


I think answer is D ,because B is smaller than A.if we put the value of x=0
Re: x is an integer.   [#permalink] 26 Aug 2018, 00:07
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