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# x is an integer.

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x is an integer. [#permalink]  15 Sep 2017, 08:21
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Question Stats:

18% (02:01) correct 81% (01:01) wrong based on 32 sessions

x is an integer.

 Quantity A Quantity B $$(-1)^{x^2}+(-1)^{x^3}+(-1)^{x^4}$$ $$(-1)^x + (-1)^{2x} + (-1)^{3x} + (-1)^{4x}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Director
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Re: x is an integer. [#permalink]  28 Sep 2017, 08:19
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Here we have that quantity A is equal to $$(-1)^{2x}+(-1)^{3x}+(-1)^{4x}$$, while column B is equal to $$(-1)^x+(-1)^{2x}+(-1)^{3x}+(-1)^{4x}$$.
Then if we subtract the equal quantities from both sides we have to compare $$1$$ and $$(-1)^x$$. Since we just know that x is an integer, which column is greater should depend on x being even or odd.

So, why the answer is B?
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Re: x is an integer. [#permalink]  28 Sep 2017, 08:38
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IlCreatore wrote:
Here we have that quantity A is equal to $$(-1)^{2x}+(-1)^{3x}+(-1)^{4x}$$, while column B is equal to $$(-1)^x+(-1)^{2x}+(-1)^{3x}+(-1)^{4x}$$.
Then if we subtract the equal quantities from both sides we have to compare $$1$$ and $$(-1)^x$$. Since we just know that x is an integer, which column is greater should depend on x being even or odd.

So, why the answer is B?

I think you have misinterpret the ques

QTy A is

$$(-1)^{x^2}+(-1)^{x^3}+(-1)^{x^4}$$

In this even if x= odd or x= even then QTY B is always greater
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Director
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Re: x is an integer. [#permalink]  29 Sep 2017, 04:19
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pranab01 wrote:
IlCreatore wrote:
Here we have that quantity A is equal to $$(-1)^{2x}+(-1)^{3x}+(-1)^{4x}$$, while column B is equal to $$(-1)^x+(-1)^{2x}+(-1)^{3x}+(-1)^{4x}$$.
Then if we subtract the equal quantities from both sides we have to compare $$1$$ and $$(-1)^x$$. Since we just know that x is an integer, which column is greater should depend on x being even or odd.

So, why the answer is B?

I think you have misinterpret the ques

QTy A is

$$(-1)^{x^2}+(-1)^{x^3}+(-1)^{x^3}$$

In this even if x= odd or x= even then QTY B is always greater

I hope they will be more properly written in the real test! Thanks!
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Re: x is an integer. [#permalink]  05 Nov 2017, 06:43
pranab01 wrote:
IlCreatore wrote:
Here we have that quantity A is equal to $$(-1)^{2x}+(-1)^{3x}+(-1)^{4x}$$, while column B is equal to $$(-1)^x+(-1)^{2x}+(-1)^{3x}+(-1)^{4x}$$.
Then if we subtract the equal quantities from both sides we have to compare $$1$$ and $$(-1)^x$$. Since we just know that x is an integer, which column is greater should depend on x being even or odd.

So, why the answer is B?

I think you have misinterpret the ques

QTy A is

$$(-1)^{x^2}+(-1)^{x^3}+(-1)^{x^4}$$

In this even if x= odd or x= even then QTY B is always greater

WHY?
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Re: x is an integer. [#permalink]  05 Nov 2017, 11:35
Expert's post
Edited the first quantity in the original post.

Thank you, Guys.

Regards
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Re: x is an integer. [#permalink]  05 Nov 2017, 17:10
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Carcass wrote:
Edited the first quantity in the orifinal post.

Thank you Guys.

Regards

the second one is also misleading since there is no addition mark b/t the middle
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Re: x is an integer. [#permalink]  05 Nov 2017, 22:19
Expert's post
Done.

Thank you so much.
Regards
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Re: x is an integer. [#permalink]  14 Nov 2017, 18:58
if we consider value of x=2 then a will be 3 and will be 4

if we consider x=3 then A will be -3 and B will be 0
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Re: x is an integer. [#permalink]  26 Aug 2018, 00:07
Carcass wrote:

x is an integer.

 Quantity A Quantity B $$(-1)^{x^2}+(-1)^{x^3}+(-1)^{x^4}$$ $$(-1)^x + (-1)^{2x} + (-1)^{3x} + (-1)^{4x}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

I think answer is D ,because B is smaller than A.if we put the value of x=0
Re: x is an integer.   [#permalink] 26 Aug 2018, 00:07
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