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Question Stats:
28% (01:47) correct
71% (01:14) wrong based on 74 sessions
x is an integer.
Quantity A 
Quantity B 
\((1)^{x^2}+(1)^{x^3}+(1)^{x^4}\) 
\((1)^x + (1)^{2x} + (1)^{3x} + (1)^{4x}\) 
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
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Re: x is an integer. [#permalink]
28 Sep 2017, 08:19
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Here we have that quantity A is equal to \((1)^{2x}+(1)^{3x}+(1)^{4x}\), while column B is equal to \((1)^x+(1)^{2x}+(1)^{3x}+(1)^{4x}\). Then if we subtract the equal quantities from both sides we have to compare \(1\) and \((1)^x\). Since we just know that x is an integer, which column is greater should depend on x being even or odd.
So, why the answer is B?



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Re: x is an integer. [#permalink]
28 Sep 2017, 08:38
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IlCreatore wrote: Here we have that quantity A is equal to \((1)^{2x}+(1)^{3x}+(1)^{4x}\), while column B is equal to \((1)^x+(1)^{2x}+(1)^{3x}+(1)^{4x}\). Then if we subtract the equal quantities from both sides we have to compare \(1\) and \((1)^x\). Since we just know that x is an integer, which column is greater should depend on x being even or odd.
So, why the answer is B? I think you have misinterpret the ques QTy A is \((1)^{x^2}+(1)^{x^3}+(1)^{x^4}\) In this even if x= odd or x= even then QTY B is always greater
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Re: x is an integer. [#permalink]
29 Sep 2017, 04:19
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pranab01 wrote: IlCreatore wrote: Here we have that quantity A is equal to \((1)^{2x}+(1)^{3x}+(1)^{4x}\), while column B is equal to \((1)^x+(1)^{2x}+(1)^{3x}+(1)^{4x}\). Then if we subtract the equal quantities from both sides we have to compare \(1\) and \((1)^x\). Since we just know that x is an integer, which column is greater should depend on x being even or odd.
So, why the answer is B? I think you have misinterpret the ques QTy A is \((1)^{x^2}+(1)^{x^3}+(1)^{x^3}\) In this even if x= odd or x= even then QTY B is always greater I hope they will be more properly written in the real test! Thanks!



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Re: x is an integer. [#permalink]
05 Nov 2017, 06:43
pranab01 wrote: IlCreatore wrote: Here we have that quantity A is equal to \((1)^{2x}+(1)^{3x}+(1)^{4x}\), while column B is equal to \((1)^x+(1)^{2x}+(1)^{3x}+(1)^{4x}\). Then if we subtract the equal quantities from both sides we have to compare \(1\) and \((1)^x\). Since we just know that x is an integer, which column is greater should depend on x being even or odd.
So, why the answer is B? I think you have misinterpret the ques QTy A is \((1)^{x^2}+(1)^{x^3}+(1)^{x^4}\) In this even if x= odd or x= even then QTY B is always greater WHY?



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Re: x is an integer. [#permalink]
05 Nov 2017, 11:35
Edited the first quantity in the original post. Thank you, Guys. Regards
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Re: x is an integer. [#permalink]
05 Nov 2017, 17:10
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Carcass wrote: Edited the first quantity in the orifinal post.
Thank you Guys.
Regards the second one is also misleading since there is no addition mark b/t the middle



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Re: x is an integer. [#permalink]
05 Nov 2017, 22:19
Done. Thank you so much. Regards
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Re: x is an integer. [#permalink]
14 Nov 2017, 18:58
i think answer is D if we consider value of x=2 then a will be 3 and will be 4
if we consider x=3 then A will be 3 and B will be 0



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Re: x is an integer. [#permalink]
26 Aug 2018, 00:07
Carcass wrote: x is an integer.
Quantity A 
Quantity B 
\((1)^{x^2}+(1)^{x^3}+(1)^{x^4}\) 
\((1)^x + (1)^{2x} + (1)^{3x} + (1)^{4x}\) 
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given. I think answer is D ,because B is smaller than A.if we put the value of x=0




Re: x is an integer.
[#permalink]
26 Aug 2018, 00:07





