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TAGS: Founder  Joined: 18 Apr 2015
Posts: 13883
GRE 1: Q160 V160 Followers: 313

Kudos [?]: 3673  , given: 12901

2
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Expert's post 00:00

Question Stats: 29% (01:42) correct 70% (01:14) wrong based on 75 sessions

x is an integer.

 Quantity A Quantity B $$(-1)^{x^2}+(-1)^{x^3}+(-1)^{x^4}$$ $$(-1)^x + (-1)^{2x} + (-1)^{3x} + (-1)^{4x}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

_________________ Director Joined: 03 Sep 2017
Posts: 518
Followers: 2

Kudos [?]: 440  , given: 66

Re: x is an integer. [#permalink]
1
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Here we have that quantity A is equal to $$(-1)^{2x}+(-1)^{3x}+(-1)^{4x}$$, while column B is equal to $$(-1)^x+(-1)^{2x}+(-1)^{3x}+(-1)^{4x}$$.
Then if we subtract the equal quantities from both sides we have to compare $$1$$ and $$(-1)^x$$. Since we just know that x is an integer, which column is greater should depend on x being even or odd.

So, why the answer is B? VP Joined: 20 Apr 2016
Posts: 1302
WE: Engineering (Energy and Utilities)
Followers: 22

Kudos [?]: 1340  , given: 251

Re: x is an integer. [#permalink]
3
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IlCreatore wrote:
Here we have that quantity A is equal to $$(-1)^{2x}+(-1)^{3x}+(-1)^{4x}$$, while column B is equal to $$(-1)^x+(-1)^{2x}+(-1)^{3x}+(-1)^{4x}$$.
Then if we subtract the equal quantities from both sides we have to compare $$1$$ and $$(-1)^x$$. Since we just know that x is an integer, which column is greater should depend on x being even or odd.

So, why the answer is B?

I think you have misinterpret the ques

QTy A is

$$(-1)^{x^2}+(-1)^{x^3}+(-1)^{x^4}$$

In this even if x= odd or x= even then QTY B is always greater
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GRE Prep Club Members of the Month:TOP 10 members of the month with highest kudos receive access to 3 months GRE Prep Club tests Director Joined: 03 Sep 2017
Posts: 518
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Kudos [?]: 440  , given: 66

Re: x is an integer. [#permalink]
1
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pranab01 wrote:
IlCreatore wrote:
Here we have that quantity A is equal to $$(-1)^{2x}+(-1)^{3x}+(-1)^{4x}$$, while column B is equal to $$(-1)^x+(-1)^{2x}+(-1)^{3x}+(-1)^{4x}$$.
Then if we subtract the equal quantities from both sides we have to compare $$1$$ and $$(-1)^x$$. Since we just know that x is an integer, which column is greater should depend on x being even or odd.

So, why the answer is B?

I think you have misinterpret the ques

QTy A is

$$(-1)^{x^2}+(-1)^{x^3}+(-1)^{x^3}$$

In this even if x= odd or x= even then QTY B is always greater

I hope they will be more properly written in the real test! Thanks!
Manager Joined: 27 Sep 2017
Posts: 111
Followers: 1

Kudos [?]: 47 , given: 4

Re: x is an integer. [#permalink]
pranab01 wrote:
IlCreatore wrote:
Here we have that quantity A is equal to $$(-1)^{2x}+(-1)^{3x}+(-1)^{4x}$$, while column B is equal to $$(-1)^x+(-1)^{2x}+(-1)^{3x}+(-1)^{4x}$$.
Then if we subtract the equal quantities from both sides we have to compare $$1$$ and $$(-1)^x$$. Since we just know that x is an integer, which column is greater should depend on x being even or odd.

So, why the answer is B?

I think you have misinterpret the ques

QTy A is

$$(-1)^{x^2}+(-1)^{x^3}+(-1)^{x^4}$$

In this even if x= odd or x= even then QTY B is always greater

WHY?
Founder  Joined: 18 Apr 2015
Posts: 13883
GRE 1: Q160 V160 Followers: 313

Kudos [?]: 3673 , given: 12901

Re: x is an integer. [#permalink]
Expert's post
Edited the first quantity in the original post.

Thank you, Guys.

Regards
_________________ Manager Joined: 27 Sep 2017
Posts: 111
Followers: 1

Kudos [?]: 47  , given: 4

Re: x is an integer. [#permalink]
1
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Carcass wrote:
Edited the first quantity in the orifinal post.

Thank you Guys.

Regards

the second one is also misleading since there is no addition mark b/t the middle
Founder  Joined: 18 Apr 2015
Posts: 13883
GRE 1: Q160 V160 Followers: 313

Kudos [?]: 3673 , given: 12901

Re: x is an integer. [#permalink]
Expert's post
Done.

Thank you so much.
Regards
_________________
Intern Joined: 10 Nov 2017
Posts: 2
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Kudos [?]: 0 , given: 0

Re: x is an integer. [#permalink]
if we consider value of x=2 then a will be 3 and will be 4

if we consider x=3 then A will be -3 and B will be 0
Intern Joined: 15 May 2018
Posts: 38
Followers: 0

Kudos [?]: 6 , given: 1

Re: x is an integer. [#permalink]
Carcass wrote:

x is an integer.

 Quantity A Quantity B $$(-1)^{x^2}+(-1)^{x^3}+(-1)^{x^4}$$ $$(-1)^x + (-1)^{2x} + (-1)^{3x} + (-1)^{4x}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

I think answer is D ,because B is smaller than A.if we put the value of x=0 Re: x is an integer.   [#permalink] 26 Aug 2018, 00:07
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