Author 
Message 
TAGS:


Moderator
Joined: 18 Apr 2015
Posts: 5126
Followers: 76
Kudos [?]:
1027
[1]
, given: 4631

x is a nonnegative number and the square root of (10 – 3x) [#permalink]
17 Sep 2017, 03:55
1
This post received KUDOS
Question Stats:
43% (01:08) correct
56% (01:33) wrong based on 57 sessions
x is a nonnegative number and the square root of (10 – 3x) is greater than x.
Quantity A 
Quantity B 
\(x\) 
\(2\) 
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
_________________
Get the 2 FREE GREPrepclub Tests




Director
Joined: 03 Sep 2017
Posts: 521
Followers: 1
Kudos [?]:
330
[1]
, given: 66

Re: x is a nonnegative number and the square root of (10 – 3x) [#permalink]
21 Sep 2017, 08:35
1
This post received KUDOS
We need to solve the equation \(sqrt(103x)>x\). Squaring both sides we get \(103x>x^2\) that can be rewritten as \(x^2+3x10<0\). The left hand side can be rewritten as \((x5)(x+2)\), thus the solution of the equation is \(5<x<2\).
Since x is non negative, among the solutions we must consider only those between 0 and 2, excluded. Thus, no matter the absolute value, column A is always smaller than 2.
Answer B



Intern
Joined: 11 Jan 2018
Posts: 44
Followers: 0
Kudos [?]:
26
[0], given: 7

Re: x is a nonnegative number and the square root of (10 – 3x) [#permalink]
28 Feb 2018, 14:56
IlCreatore wrote: We need to solve the equation \(sqrt(103x)>x\). Squaring both sides we get \(103x>x^2\) that can be rewritten as \(x^2+3x10<0\). The left hand side can be rewritten as \((x5)(x+2)\), thus the solution of the equation is \(5<x<2\).
Since x is non negative, among the solutions we must consider only those between 0 and 2, excluded. Thus, no matter the absolute value, column A is always smaller than 2.
Answer B Good explanation. Yes I will go with B as well.
_________________
Persistence >>>>>>> Success
Don't say thanks, just give KUDOS. 1 kudos = 1000 Thanks



Manager
Joined: 26 Jun 2017
Posts: 104
Followers: 0
Kudos [?]:
38
[0], given: 38

Re: x is a nonnegative number and the square root of (10 – 3x) [#permalink]
04 Mar 2018, 02:11
so
Attachments
5656565.jpg [ 131.56 KiB  Viewed 1044 times ]
_________________
What you think, you become.



Moderator
Joined: 18 Apr 2015
Posts: 5126
Followers: 76
Kudos [?]:
1027
[0], given: 4631

Re: x is a nonnegative number and the square root of (10 – 3x) [#permalink]
05 Mar 2018, 14:47
Please boxing, your replies are very delightful. However, please as a test and not as a screenshot. Thank you so much for your collaboration. The board is cleaner that way. regards
_________________
Get the 2 FREE GREPrepclub Tests



Intern
Joined: 28 Nov 2017
Posts: 44
Followers: 1
Kudos [?]:
30
[1]
, given: 22

Re: x is a nonnegative number and the square root of (10 – 3x) [#permalink]
29 Mar 2018, 00:39
1
This post received KUDOS
Short & Quick way to get the Answer is :
3x has to be less than 10 as we can't find out the Sqaure root of a a negative number so x can only take values of 0,1,2 & exclude non negative solutions so 2 is rejected. Answer b



Manager
Joined: 22 Feb 2018
Posts: 118
Followers: 2
Kudos [?]:
71
[1]
, given: 14

Re: x is a nonnegative number and the square root of (10 – 3x) [#permalink]
01 Apr 2018, 17:21
1
This post received KUDOS
Answer: B Sure root of 10  3x is greater than x and x is a nonnegative integer. First, as x is nonnegative, thus x equals x in A. We try numbers. The minimum value for x can be 0. If x = 0, square root of 103x equals 10, which is greater than x. If x = 1, 103 is greater than 1 If x = 2, 10 6 is not greater than 2. So, x can be either 0 or 1 and always less than 2. The answer is B.
_________________
Follow your heart



Intern
Joined: 20 Mar 2018
Posts: 34
Followers: 1
Kudos [?]:
24
[0], given: 2

Re: x is a nonnegative number and the square root of (10 – 3x) [#permalink]
04 Apr 2018, 07:38
Yiddo_Bhushan wrote: Short & Quick way to get the Answer is :
3x has to be less than 10 as we can't find out the Sqaure root of a a negative number so x can only take values of 0,1,2 & exclude non negative solutions so 2 is rejected. Answer b However, it is not mentioned that x has to be an integer. x can be just less than 10/3 or 3 for that matter.



Intern
Joined: 20 Mar 2018
Posts: 34
Followers: 1
Kudos [?]:
24
[1]
, given: 2

Re: x is a nonnegative number and the square root of (10 – 3x) [#permalink]
04 Apr 2018, 07:41
1
This post received KUDOS
Given: x>0 and \sqrt{(103x)} > x gives 5<x<2
Ignoring negative solutions. 0<x<2 and x would be less than 2



Intern
Joined: 02 Dec 2018
Posts: 10
Followers: 0
Kudos [?]:
0
[0], given: 7

Re: x is a nonnegative number and the square root of (10 – 3x) [#permalink]
07 Dec 2018, 15:23
Hey guys, I understand your solution, but could you point out the fallacy or mistake in my solution.
sqrt(103x) > x x>=0 so sqrt(103x)>0 then 103x >0 Thus x < (10/3)
So D because the absolute value of x can be greater than 2 or smaller than 2.




Re: x is a nonnegative number and the square root of (10 – 3x)
[#permalink]
07 Dec 2018, 15:23





