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# x^2=16

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Moderator
Joined: 18 Apr 2015
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x^2=16 [#permalink]  16 May 2018, 09:06
Expert's post
00:00

Question Stats:

66% (00:13) correct 33% (00:16) wrong based on 12 sessions
$$x^2=16$$

$$y^3=64$$

 Quantity A Quantity B x y

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Manager
Joined: 26 Jan 2018
Posts: 182
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Kudos [?]: 110 [1] , given: 3

Re: x^2=16 [#permalink]  16 May 2018, 09:24
1
KUDOS
x can be + or - 4 as it is square

But y is +4 as it is cube. And if cube is +ve then the number s also +ve.

However if A is positive, A = B
else A is less than B.

Hence cannot be determined
GRE Instructor
Joined: 10 Apr 2015
Posts: 1543
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Kudos [?]: 1468 [1] , given: 8

Re: x^2=16 [#permalink]  13 Jan 2019, 11:20
1
KUDOS
Expert's post
Carcass wrote:
$$x^2=16$$

$$y^3=64$$

 Quantity A Quantity B x y

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

If $$x^2=16$$, then EITHER $$x = 4$$ OR $$x = -4$$
If $$y^3=64$$, then $$y=4$$

This brings up two possible cases:
If $$x = 4$$ and $$y=4$$, then the two quantities are EQUAL
If $$x = -4$$ and $$y=4$$, then Quantity B is GREATER

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com

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Re: x^2=16   [#permalink] 13 Jan 2019, 11:20
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# x^2=16

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