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# x < 0

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Founder
Joined: 18 Apr 2015
Posts: 13918
GRE 1: Q160 V160
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Kudos [?]: 3687 [0], given: 12942

x < 0 [#permalink]  16 Apr 2018, 15:08
Expert's post
00:00

Question Stats:

52% (00:23) correct 47% (00:27) wrong based on 40 sessions

Last edited by Carcass on 27 Dec 2018, 09:47, edited 2 times in total.
Edited the OA
Manager
Joined: 29 Nov 2017
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GRE 1: Q142 V146
WE: Information Technology (Computer Software)
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Kudos [?]: 94 [0], given: 99

Re: x < 0 [#permalink]  16 May 2018, 02:07
if X is negative then if we suppose entity A will be over all positive then A is greater than B.

Last edited by IshanGre on 16 May 2018, 05:40, edited 1 time in total.
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Kudos [?]: 3037 [1] , given: 394

Re: x < 0 [#permalink]  16 May 2018, 03:03
1
KUDOS
Expert's post
IshanGre wrote:
if X is negative the if we suppose entity A will be over all positive then A is greater than B.

This is actually a tricky question

Given that x<0

Quantity A: $$x^2-x^5 = x^2(1-x^3)$$ now $$x^2$$ is always positve as $$x \neq 0$$ but $$1-x^3$$ may or maynot be positive.

If $$|x| > 0$$ then $$1-x^3$$ is negative.

Try plugging values: $$x=-0.5$$

Quanity A: 0.21875 here quantity A is greater.

$$x=-1.5$$

Quanity A: -5.34375 here quantity B is greater.

Hence the correct option is D.
_________________

Sandy
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Joined: 08 Apr 2018
Posts: 44
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Kudos [?]: 17 [1] , given: 15

Re: x < 0 [#permalink]  16 May 2018, 11:38
1
KUDOS
sandy wrote:
IshanGre wrote:
if X is negative the if we suppose entity A will be over all positive then A is greater than B.

This is actually a tricky question

Given that x<0

Quantity A: $$x^2-x^5 = x^2(1-x^3)$$ now $$x^2$$ is always positve as $$x \neq 0$$ but $$1-x^3$$ may or maynot be positive.

If $$|x| > 0$$ then $$1-x^3$$ is negative.

Try plugging values: $$x=-0.5$$

Quanity A: 0.21875 here quantity A is greater.

$$x=-1.5$$

Quanity A: -5.34375 here quantity B is greater.

Hence the correct option is D.

Hi Sandy, if the correct answer is D, can you please update the Reveal Answer to D? It is still A.
Intern
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Kudos [?]: 6 [0], given: 1

Re: x < 0 [#permalink]  01 Jul 2018, 21:23
Carcass wrote:
$$x < 0$$

 Quantity A Quantity B $$x^2 - x^5$$ $$0$$

A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

answer must be a in all cases
Intern
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Posts: 3
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Kudos [?]: 3 [1] , given: 0

Re: x < 0 [#permalink]  03 Jul 2018, 04:25
1
KUDOS
Founder
Joined: 18 Apr 2015
Posts: 13918
GRE 1: Q160 V160
Followers: 315

Kudos [?]: 3687 [0], given: 12942

Re: x < 0 [#permalink]  04 Jul 2018, 00:59
Expert's post
Re: x < 0   [#permalink] 04 Jul 2018, 00:59
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