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x < 0 [#permalink] New post 16 Apr 2018, 15:08
Expert's post
00:00

Question Stats:

52% (00:23) correct 47% (00:27) wrong based on 40 sessions

Last edited by Carcass on 27 Dec 2018, 09:47, edited 2 times in total.
Edited the OA
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Re: x < 0 [#permalink] New post 16 May 2018, 02:07
if X is negative then if we suppose entity A will be over all positive then A is greater than B.

Last edited by IshanGre on 16 May 2018, 05:40, edited 1 time in total.
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Re: x < 0 [#permalink] New post 16 May 2018, 03:03
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IshanGre wrote:
if X is negative the if we suppose entity A will be over all positive then A is greater than B.



This is actually a tricky question

Given that x<0

Quantity A: \(x^2-x^5 = x^2(1-x^3)\) now \(x^2\) is always positve as \(x \neq 0\) but \(1-x^3\) may or maynot be positive.

If \(|x| > 0\) then \(1-x^3\) is negative.

Try plugging values: \(x=-0.5\)

Quanity A: 0.21875 here quantity A is greater.


\(x=-1.5\)

Quanity A: -5.34375 here quantity B is greater.


Hence the correct option is D.
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Re: x < 0 [#permalink] New post 16 May 2018, 11:38
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sandy wrote:
IshanGre wrote:
if X is negative the if we suppose entity A will be over all positive then A is greater than B.



This is actually a tricky question

Given that x<0

Quantity A: \(x^2-x^5 = x^2(1-x^3)\) now \(x^2\) is always positve as \(x \neq 0\) but \(1-x^3\) may or maynot be positive.

If \(|x| > 0\) then \(1-x^3\) is negative.

Try plugging values: \(x=-0.5\)

Quanity A: 0.21875 here quantity A is greater.


\(x=-1.5\)

Quanity A: -5.34375 here quantity B is greater.


Hence the correct option is D.


Hi Sandy, if the correct answer is D, can you please update the Reveal Answer to D? It is still A.
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Re: x < 0 [#permalink] New post 01 Jul 2018, 21:23
Carcass wrote:
\(x < 0\)

Quantity A
Quantity B
\(x^2 - x^5\)
\(0\)


A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

answer must be a in all cases
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Re: x < 0 [#permalink] New post 03 Jul 2018, 04:25
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Answer is A not D
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Re: x < 0 [#permalink] New post 04 Jul 2018, 00:59
Expert's post
Re: x < 0   [#permalink] 04 Jul 2018, 00:59
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