IshanGre wrote:
if X is negative the if we suppose entity A will be over all positive then A is greater than B.
This is actually a tricky question
Given that x<0
Quantity A: \(x^2-x^5 = x^2(1-x^3)\) now \(x^2\) is always positve as \(x \neq 0\) but \(1-x^3\) may or maynot be positive.
If \(|x| > 0\) then \(1-x^3\) is negative.
Try plugging values: \(x=-0.5\)
Quanity A: 0.21875 here quantity A is greater.
\(x=-1.5\)
Quanity A: -5.34375 here quantity B is greater.
Hence the correct option is D.
_________________
Sandy
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52% (00:23) correct
