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# x > 1

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Founder
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x > 1 [#permalink]  06 Mar 2018, 14:15
Expert's post
00:00

Question Stats:

86% (00:12) correct 13% (00:11) wrong based on 22 sessions

$$x > 1$$

 Quantity A Quantity B $$x(x^2)^4$$ $$(x^3)^3$$

Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

_________________
Founder
Joined: 18 Apr 2015
Posts: 6874
Followers: 114

Kudos [?]: 1332 [0], given: 6293

Re: x > 1 [#permalink]  06 Mar 2018, 14:24
Expert's post
Explanation

The best way to tackle this question is to observe it.

The first thought you could have is picking numbers but the question would become long and tedious, even though could be feasible.

You should pick positive integers or positive fractions but the calculation is long.

Knowing, instead, the rule of the exponents the solution is easier.

Quantity A $$x*x^8 = x^9$$
Quantity B $$x^{3*3} = x^9$$
_________________
Intern
Joined: 28 Feb 2018
Posts: 30
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Kudos [?]: 2 [1] , given: 0

Re: x > 1 [#permalink]  11 Mar 2018, 07:15
1
KUDOS
Quantity A x*x^8 = x^9
Quantity B x^{3*3} = x^9
_________________
Intern
Joined: 28 Feb 2018
Posts: 30
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Kudos [?]: 2 [0], given: 0

Re: x > 1 [#permalink]  12 Mar 2018, 01:23
Quantity A x*x^8 = x^9
Quantity B x^{3*3} = x^9
Director
Joined: 20 Apr 2016
Posts: 900
WE: Engineering (Energy and Utilities)
Followers: 11

Kudos [?]: 666 [1] , given: 147

Re: x > 1 [#permalink]  08 Nov 2018, 03:36
1
KUDOS
Carcass wrote:
$$x > 1$$

 Quantity A Quantity B $$x(x^2)^4$$ $$(x^3)^3$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Explanation::

QTY A : $$x(x^2)^4 = x^9$$

QTY B : $$(x^3)^3 = x^9$$

Hence QTY A = QTY B

Option C
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Intern
Joined: 04 Nov 2018
Posts: 44
Followers: 0

Kudos [?]: 6 [0], given: 8

Re: x > 1 [#permalink]  10 Nov 2018, 09:36
Carcass wrote:
$$x > 1$$

 Quantity A Quantity B $$x(x^2)^4$$ $$(x^3)^3$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Why is it wrong that I did first did $$(x^1 *x^2)$$= $$(x^3)$$ then $$(x^3)^4$$=x^12?
Intern
Joined: 17 Oct 2018
Posts: 18
Followers: 0

Kudos [?]: 3 [1] , given: 23

Re: x > 1 [#permalink]  15 Nov 2018, 04:56
1
KUDOS
Mercychee wrote:

Why is it wrong that I did first did $$(x^1 *x^2)$$= $$(x^3)$$ then $$(x^3)^4$$=x^12?

BODMAS/PEMDAS: Solve brackets or parentheses first. The 4 in $$(x^2)^4$$ is a part of the bracket that requires first priority while solving.
Intern
Joined: 07 Aug 2016
Posts: 42
Followers: 0

Kudos [?]: 16 [0], given: 0

Re: x > 1 [#permalink]  19 Nov 2018, 16:02
x (x^2)^4 = x * x^ 8 = x^9

(x^3)^3 = x^9

Both quantities are equal.

Re: x > 1   [#permalink] 19 Nov 2018, 16:02
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