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x > 1 [#permalink] New post 06 Mar 2018, 14:15
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Question Stats:

88% (00:13) correct 11% (00:00) wrong based on 17 sessions


\(x > 1\)

Quantity A
Quantity B
\(x(x^2)^4\)
\((x^3)^3\)


Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: x > 1 [#permalink] New post 06 Mar 2018, 14:24
Expert's post
Explanation

The best way to tackle this question is to observe it.

The first thought you could have is picking numbers but the question would become long and tedious, even though could be feasible.

You should pick positive integers or positive fractions but the calculation is long.

Knowing, instead, the rule of the exponents the solution is easier.

Quantity A \(x*x^8 = x^9\)
Quantity B \(x^{3*3} = x^9\)
C is the answer
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Re: x > 1 [#permalink] New post 11 Mar 2018, 07:15
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Quantity A x*x^8 = x^9
Quantity B x^{3*3} = x^9
C is the answer
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Re: x > 1 [#permalink] New post 12 Mar 2018, 01:23
Quantity A x*x^8 = x^9
Quantity B x^{3*3} = x^9
C is the answer
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Re: x > 1 [#permalink] New post 08 Nov 2018, 03:36
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Carcass wrote:
\(x > 1\)

Quantity A
Quantity B
\(x(x^2)^4\)
\((x^3)^3\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.



Explanation::

QTY A : \(x(x^2)^4 = x^9\)

QTY B : \((x^3)^3 = x^9\)

Hence QTY A = QTY B

Option C
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Re: x > 1 [#permalink] New post 10 Nov 2018, 09:36
Carcass wrote:
\(x > 1\)

Quantity A
Quantity B
\(x(x^2)^4\)
\((x^3)^3\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


Why is it wrong that I did first did \((x^1 *x^2)\)= \((x^3)\) then \((x^3)^4\)=x^12?
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Re: x > 1 [#permalink] New post 15 Nov 2018, 04:56
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Mercychee wrote:

Why is it wrong that I did first did \((x^1 *x^2)\)= \((x^3)\) then \((x^3)^4\)=x^12?


BODMAS/PEMDAS: Solve brackets or parentheses first. The 4 in \((x^2)^4\) is a part of the bracket that requires first priority while solving.
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Re: x > 1 [#permalink] New post 19 Nov 2018, 16:02
x (x^2)^4 = x * x^ 8 = x^9

(x^3)^3 = x^9

Both quantities are equal.

Answer choice C
Re: x > 1   [#permalink] 19 Nov 2018, 16:02
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