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Question Stats:
58% (00:50) correct
41% (00:52) wrong based on 82 sessions
\(x > 1\)
Quantity A 
Quantity B 
\(\frac{x+5}{x}\) 
\(\frac{(x1) +5}{x1}\) 
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
Last edited by amorphous on 20 Sep 2018, 01:58, edited 2 times in total.
Edit the OA




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Here we are asked to compare \(\frac{x+5}{x}\) and \(\frac{x+4}{x1}\). Given that x > 1, we just have to try and substitute integers from 2 on. This leads to the result that quantity B is greater. Answer B



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I took X>1 as 3/2 = 1.5
and it turns out that option A is greater than B at this scenario.
However when I took 2 and 3 ..option B indeed truned out to be greater than A.
hence answer should be D.
Please clarify.



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Think theoretically, it is much better than plugin number this time. It is cumbersome. QA \(\frac{x}{x} + \frac{5}{x}\) QB \(\frac{(x1)}{(x1)} + \frac{5}{(x1)}\) \(\frac{x}{x}\) and \(\frac{(x1)}{(x1)}\) are both equal to one so we will end up with \(\frac{5}{x}\) and \(\frac{5}{x1}\) Now, if you plug an integer B > A but if you plug a fraction A > B. So the answer is D but the OE in the book is B. Clearly a mistake. Hope this helps. Regards
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Carcass wrote: Think theoretically, it is much better than plugin number this time. It is cumbersome.
QA \(\frac{x}{x} + \frac{5}{x}\)
QB \(\frac{(x1)}{(x1)} + \frac{5}{(x1)}\)
\(\frac{x}{x}\) and \(\frac{(x1)}{(x1)}\) are both equal to one
so we will end up with \(\frac{5}{x}\) and \(\frac{5}{x1}\)
Now, if you plug an integer B > A but if you plug a fraction A > B. So the answer is D but the OE in the book is B.
Clearly a mistake. Hope this helps.
Regards Great looks like I am learning now ..Thanks to this forum .what is OE book?



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Actually the explanation I gave you. It takes into account only integers greater than one, which is impossible because you must take in account even fractions. Hope this helps. Regards
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Carcass wrote: Actually the explanation I gave you. It takes into account only integers greater than one, which is impossible because you must take in account even fractions.
Hope this helps. Regards Thanks



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I can't seem to make a clear decision. Everytime I am trying out any value I am getting B>A. Now, let's say after simplification we are dealing with
Quantity A Quantity B
1/X on side 1/ (X1)
But if I take let's say X to be a fraction i.e. 8/3 (X has to be greater than 1) then on side A we get 3/8= 0.375 and on side B we get 3/5= 0.6. in this case B>A
Again, when I try out an integer, say, 5, I get 1/5 on side A and 1/4 on side B.
In fact, when I apply the theory I get, that quantity B should be greater. Since X>1 that means X is a positive number. So, when X is in the denominator the result should be less than when a value less than X is in the denominator the result should be greater, provided that the numerator remains the same.
Could please explain at length. Cause I can't figure out a case where A>B.
Sincerely, Scrat



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IshanGre wrote: Carcass wrote: Think theoretically, it is much better than plugin number this time. It is cumbersome.
QA \(\frac{x}{x} + \frac{5}{x}\)
QB \(\frac{(x1)}{(x1)} + \frac{5}{(x1)}\)
\(\frac{x}{x}\) and \(\frac{(x1)}{(x1)}\) are both equal to one
so we will end up with \(\frac{5}{x}\) and \(\frac{5}{x1}\)
Now, if you plug an integer B > A but if you plug a fraction A > B. So the answer is D but the OE in the book is B.
Clearly a mistake. Hope this helps.
Regards Great looks like I am learning now ..Thanks to this forum .what is OE book? This explanation is not right. Clearly, with x > 1, B is always greater, regardless of what you take for x, an integer or fraction>1 even after reducing it to \frac{5}{x} and \frac{5}{(x1)}, given that x>1 it can be clearly observed that \frac{5}{(x1)} has a smaller denominator than \frac{5}{x} while the numerator in both cases is same. Hence \frac{5}{(x1)} has to be greater. Correct answer is B.









