IshanGre wrote:
Carcass wrote:
Think theoretically, it is much better than plug-in number this time. It is cumbersome.
QA \(\frac{x}{x} + \frac{5}{x}\)
QB \(\frac{(x-1)}{(x-1)} + \frac{5}{(x-1)}\)
\(\frac{x}{x}\) and \(\frac{(x-1)}{(x-1)}\) are both equal to one
so we will end up with \(\frac{5}{x}\) and \(\frac{5}{x-1}\)
Now, if you plug an integer B > A but if you plug a fraction A > B. So the answer is D but the OE in the book is B.
Clearly a mistake. Hope this helps.
Regards
Great-- looks like I am learning now
..Thanks to this forum .what is OE book?
This explanation is not right. Clearly, with x > 1, B is always greater, regardless of what you take for x, an integer or fraction>1
even after reducing it to
\frac{5}{x} and \frac{5}{(x-1)}, given that x>1 it can be clearly observed that \frac{5}{(x-1)} has a smaller denominator than \frac{5}{x} while the numerator in both cases is same. Hence \frac{5}{(x-1)} has to be greater. Correct answer is B.