ExplanationStarting from quantity A we do know that any value we substitute in X will always positive due to its square. On the other hand quanity B coulb be also a negative number

Moreover, we should take in account the value could be a fraction such as \(\frac{1}{2}\) or an integer such as 5

A) \(\frac{1}{2^2}\) + 1 = 1.25

Or \(5^2\) + 1 = 26

B) 2* \(\frac{1}{2}\) - 1 = 0

Or using 5 we do have 10 - 1 = 9

Or -5 we do have -10 - 1 =-11

Quantity A is always greater.

As a side note, the OE is too cumbersome

an excerpt

**Quote:**

The left-hand side of the comparison is the square of a number. Since the square of a number is always greater than or equal to 0, and 0 is greater than the −1, the simpliﬁed comparison is the inequality and the resulting 2 (x − 1) > −1 the relationship is greater than (>). In reverse order, each simpliﬁcation step implies the inequality greater than (>) in the preceding comparison. Therefore, Quantity A is greater than Quantity B.

As you can see is difficult. Instead, stick with the basic. In this case, picking numbers and find the fastest solution within 30 seconds and move on.

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