It is currently 18 Nov 2018, 23:14

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# x < 0

 Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:
Moderator
Joined: 18 Apr 2015
Posts: 4914
Followers: 74

Kudos [?]: 978 [0], given: 4499

x < 0 [#permalink]  26 Aug 2017, 01:59
Expert's post
00:00

Question Stats:

87% (00:38) correct 12% (01:28) wrong based on 24 sessions

$$x < 0$$

 Quantity A Quantity B $$x^2$$ $$- 5x + 6$$ $$x^2$$ $$- 9x + 20$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

_________________
GRE Instructor
Joined: 10 Apr 2015
Posts: 1177
Followers: 44

Kudos [?]: 1054 [1] , given: 6

Re: x < 0 [#permalink]  27 Aug 2017, 04:53
1
This post received
KUDOS
Expert's post
Carcass wrote:
x < 0

 Quantity A Quantity B $$x^2$$ – 5x + 6 $$x^2$$ – 9x + 20

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Let's use matching operations

Given:
Quantity A: x² - 5x + 6
Quantity B: x² - 9x + 20

Subtract x² from both quantities to get:
Quantity A: -5x + 6
Quantity B: -9x + 20

Add 9x to both quantities to get:
Quantity A: 4x + 6
Quantity B: 20

Subtract 6 from both quantities to get:
Quantity A: 4x
Quantity B: 14

Divide both quantities by 4 to get:
Quantity A: x
Quantity B: 3.5

Since we're told that x is NEGATIVE, it must be the case that Quantity B is greater.

Answer: B

RELATED VIDEO FROM OUR COURSE

_________________

Brent Hanneson – Creator of greenlighttestprep.com

Sign up for our free GRE Question of the Day emails

Intern
Joined: 09 Nov 2018
Posts: 49
Followers: 0

Kudos [?]: 2 [0], given: 1

Re: x < 0 [#permalink]  13 Nov 2018, 17:50
Is there any other approach?
GRE Instructor
Joined: 10 Apr 2015
Posts: 1177
Followers: 44

Kudos [?]: 1054 [1] , given: 6

Re: x < 0 [#permalink]  13 Nov 2018, 18:09
1
This post received
KUDOS
Expert's post
AE wrote:
Is there any other approach?

You could try testing numbers.

More here:

_________________

Brent Hanneson – Creator of greenlighttestprep.com

Sign up for our free GRE Question of the Day emails

Re: x < 0   [#permalink] 13 Nov 2018, 18:09
Display posts from previous: Sort by

# x < 0

 Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group Kindly note that the GRE® test is a registered trademark of the Educational Testing Service®, and this site has neither been reviewed nor endorsed by ETS®.