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x < 0 [#permalink] New post 26 Aug 2017, 01:59
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Question Stats:

87% (00:38) correct 12% (01:28) wrong based on 24 sessions


\(x < 0\)

Quantity A
Quantity B
\(x^2\) \(- 5x + 6\)
\(x^2\) \(- 9x + 20\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: x < 0 [#permalink] New post 27 Aug 2017, 04:53
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Carcass wrote:
x < 0

Quantity A
Quantity B
\(x^2\) – 5x + 6
\(x^2\) – 9x + 20


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


Let's use matching operations

Given:
Quantity A: x² - 5x + 6
Quantity B: x² - 9x + 20

Subtract x² from both quantities to get:
Quantity A: -5x + 6
Quantity B: -9x + 20

Add 9x to both quantities to get:
Quantity A: 4x + 6
Quantity B: 20

Subtract 6 from both quantities to get:
Quantity A: 4x
Quantity B: 14

Divide both quantities by 4 to get:
Quantity A: x
Quantity B: 3.5

Since we're told that x is NEGATIVE, it must be the case that Quantity B is greater.

Answer: B

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Re: x < 0 [#permalink] New post 13 Nov 2018, 17:50
Is there any other approach?
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Re: x < 0 [#permalink] New post 13 Nov 2018, 18:09
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AE wrote:
Is there any other approach?


You could try testing numbers.

More here:

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Re: x < 0   [#permalink] 13 Nov 2018, 18:09
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