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Manager
Joined: 22 Jul 2018
Posts: 79
Followers: 0
Kudos [?]:
13
[0], given: 42

Question Stats:
33% (00:42) correct
66% (01:13) wrong based on 33 sessions
\(x=4\)\(\sqrt{(x^3+6x^2)}\)
Quantity A 
Quantity B 
The sum of all possible roots of x 
1 
Quantity A is greater Quantity B is greater The two quantities are equal The relationship cannot be determined from the information given




Manager
Joined: 22 Jul 2018
Posts: 79
Followers: 0
Kudos [?]:
13
[0], given: 42

Please explain the solution



Founder
Joined: 18 Apr 2015
Posts: 7737
Followers: 143
Kudos [?]:
1593
[0], given: 7027

Please see how to format a question in the right manner . https://greprepclub.com/forum/qqhowto ... 2357.htmlThank you so much
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Supreme Moderator
Joined: 01 Nov 2017
Posts: 370
Followers: 5
Kudos [?]:
123
[0], given: 4

Sawant91 wrote: \(x=4\)\(\sqrt{(x^3+6x^2)}\)
Quantity A 
Quantity B 
The sum of all possible roots of x 
1 
Quantity A is greater Quantity B is greater The two quantities are equal The relationship cannot be determined from the information given the answer depends on what 4 means is it 4th root, or 4* something
_________________
Some useful Theory. 1. Arithmetic and Geometric progressions : https://greprepclub.com/forum/progressionsarithmeticgeometricandharmonic11574.html#p27048 2. Effect of Arithmetic Operations on fraction : https://greprepclub.com/forum/effectsofarithmeticoperationsonfractions11573.html?sid=d570445335a783891cd4d48a17db9825 3. Remainders : https://greprepclub.com/forum/remainderswhatyoushouldknow11524.html 4. Number properties : https://greprepclub.com/forum/numberpropertyallyourequire11518.html 5. Absolute Modulus and Inequalities : https://greprepclub.com/forum/absolutemodulusabetterunderstanding11281.html



Intern
Joined: 21 Nov 2018
Posts: 21
Followers: 0
Kudos [?]:
3
[0], given: 1

If we consider that the expression given is the 4th root , then the answer should be C . Can someone please explain how is the answer A ?



Intern
Joined: 07 Dec 2018
Posts: 3
Followers: 0
Kudos [?]:
0
[0], given: 2

kunalkmr62 wrote: If we consider that the expression given is the 4th root , then the answer should be C . Can someone please explain how is the answer A ? Agree, For the 4th root, x can be solved for 3&2, hence sum of the roots is 1, so C should be the option.



Manager
Joined: 22 Jul 2018
Posts: 79
Followers: 0
Kudos [?]:
13
[0], given: 42

It is said sum of all possible root: I am getting possible values 1,3 As 3 is greater than 1 hence answer is A



Supreme Moderator
Joined: 01 Nov 2017
Posts: 370
Followers: 5
Kudos [?]:
123
[0], given: 4

Sawant91 wrote: \(x=4\)\(\sqrt{(x^3+6x^2)}\)
Quantity A 
Quantity B 
The sum of all possible roots of x 
1 
Quantity A is greater Quantity B is greater The two quantities are equal The relationship cannot be determined from the information given The question could mean two things.. (I) If it is what it is given \(x=4\)\(\sqrt{(x^3+6x^2)}\) Square both sides  \(x^2=16(x^3+6x^2).......16x^395x^2=0....x^2(16x95)=0\).. Sum of roots = \(0+\frac{95}{16}\) so A>B (II) If there is a typo and it meant $th root and not 4*.. so take the 4th power  \(x^4=x^3+6x^2......x^4x^36x^2=0.....x^2(x3)(x+2)=0\) Hence, the sum is 0+32=1 here A=B.. so C
_________________
Some useful Theory. 1. Arithmetic and Geometric progressions : https://greprepclub.com/forum/progressionsarithmeticgeometricandharmonic11574.html#p27048 2. Effect of Arithmetic Operations on fraction : https://greprepclub.com/forum/effectsofarithmeticoperationsonfractions11573.html?sid=d570445335a783891cd4d48a17db9825 3. Remainders : https://greprepclub.com/forum/remainderswhatyoushouldknow11524.html 4. Number properties : https://greprepclub.com/forum/numberpropertyallyourequire11518.html 5. Absolute Modulus and Inequalities : https://greprepclub.com/forum/absolutemodulusabetterunderstanding11281.html



Intern
Joined: 12 Nov 2018
Posts: 25
Followers: 0
Kudos [?]:
8
[0], given: 17

''x2=16(x3+6x2).......16x3−95x2=0....x2(16x−95)=0'' how is the above possible , i.e. ( 95x)?



Supreme Moderator
Joined: 01 Nov 2017
Posts: 370
Followers: 5
Kudos [?]:
123
[0], given: 4

JelalHossain wrote: ''x2=16(x3+6x2).......16x3−95x2=0....x2(16x−95)=0'' how is the above possible , i.e. ( 95x)? \(\(x^2=16(x^3+6x^2).......16x^395x^2=0....x^2(16x95)=0\)\) Take out x^2 from \(16x^395x^2=0......x^2*16xx^2*95=x^2(16x95)=0\)
_________________
Some useful Theory. 1. Arithmetic and Geometric progressions : https://greprepclub.com/forum/progressionsarithmeticgeometricandharmonic11574.html#p27048 2. Effect of Arithmetic Operations on fraction : https://greprepclub.com/forum/effectsofarithmeticoperationsonfractions11573.html?sid=d570445335a783891cd4d48a17db9825 3. Remainders : https://greprepclub.com/forum/remainderswhatyoushouldknow11524.html 4. Number properties : https://greprepclub.com/forum/numberpropertyallyourequire11518.html 5. Absolute Modulus and Inequalities : https://greprepclub.com/forum/absolutemodulusabetterunderstanding11281.html









