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Quantity A is greater Quantity B is greater The two quantities are equal The relationship cannot be determined from the information given

The question could mean two things.. (I) If it is what it is given- \(x=4\)\(\sqrt{(x^3+6x^2)}\) Square both sides - \(x^2=16(x^3+6x^2).......16x^3-95x^2=0....x^2(16x-95)=0\).. Sum of roots = \(0+\frac{95}{16}\) so A>B (II) If there is a typo and it meant $th root and not 4*.. so take the 4th power - \(x^4=x^3+6x^2......x^4-x^3-6x^2=0.....x^2(x-3)(x+2)=0\) Hence, the sum is 0+3-2=1 here A=B.. so C
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