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x > 1 [#permalink] New post 24 Feb 2017, 02:23
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Question Stats:

72% (00:32) correct 27% (00:35) wrong based on 54 sessions


\(X > 1\)

Quantity A
Quantity B
\(\frac{x}{(x+1)}\)
\(\frac{-x}{1-x}\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: x > 1 [#permalink] New post 28 Feb 2017, 16:12
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Explanation

Here we have \(x > 1\).

Now we can say that \(x < x+1\). So rewriting \(\frac{x}{x+1} < 1\) . Hence Quantity A is always less than 1.

Now we can say that \(x > x-1\). So rewriting \(\frac{x}{x-1} > 1\) . Multiplying -1 to the numerator or denominator \(\frac{-x}{1-x} > 1\). Hence Quantity B is always greater than 1.

So combining these two Quantity A < 1 < Quantity B. Hence option B is correct.
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Re: x > 1 [#permalink] New post 28 Mar 2017, 17:14
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Carcass wrote:


\(X > 1\)

Quantity A
Quantity B
\(\frac{x}{(x+1)}\)
\(\frac{-x}{1-x}\)




Quantity A: x/(x+1)
Quantity B: -x/(1-x)

First recognize that we can rewrite quantity B by factoring out a -1 from the numerator and denominator.
That is: -x = (-1)(x) and 1-x = -1(-1 + x) = -1(x - 1)
So, -x/(1-x) = (-1)(x)/(-1)(x - 1) = x/(x - 1)

So we get:
Quantity A: x/(x + 1)
Quantity B: x/(x - 1)

Now let's find a common denominator.
To do so, we'll take Quantity A and multiply numerator and denominator by (x - 1)
And we'll take Quantity B and multiply numerator and denominator by (x + 1)

When we do this, we get:
Quantity A: (x² - x)/(x² - 1)
Quantity B: (x² + x)/(x² - 1)

Next, since x > 1, we know that x² > 1, which means x² - 1 is POSITIVE
As such, we can multiply both quantities by x² - 1 to get:
Quantity A: x² - x
Quantity B: x² + x

Now it's pretty easy from here. Subtract x² from both quantities to get:
Quantity A: -x
Quantity B: x

Add x to both quantities to get:
Quantity A: 0
Quantity B: 2x

Since x is POSITIVE, 2x must be POSITIVE, which means the correct answer is B

Cheers,
Brent
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Re: x > 1 [#permalink] New post 16 Mar 2018, 13:15
correct: B
x is a positive integer, so x+1 is more than x, and x divided by x+1 is something less than 1
we can write -x/ 1-x as x / x-1 by multiplying both the numerator and the denominator by -1. As x is a positive integer, x-1 is less than x and x divided by a thing less than x is something more than 1. So B is bigger than A.
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Re: x > 1 [#permalink] New post 24 Apr 2018, 18:52
X/X+1 ? -X/1-X
As we know x>1
So, B both A nd B will always be +ve
Re write B as X/X-1
now both the numerators are equal. W just have to compare denominator now
As X-1< X+1(We know that X>1, so X can not be negative or 1)
Hence B > A
Re: x > 1   [#permalink] 24 Apr 2018, 18:52
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