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x + 32Y

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Founder
Founder
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Joined: 18 Apr 2015
Posts: 13919
GRE 1: Q160 V160
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Kudos [?]: 3687 [0], given: 12942

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x + 32Y [#permalink] New post 14 May 2018, 12:18
Expert's post
00:00

Question Stats:

97% (00:21) correct 2% (09:42) wrong based on 36 sessions
1 KUDOS received
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Kudos [?]: 4777 [1] , given: 70

Re: x + 32Y [#permalink] New post 15 May 2018, 13:22
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Expert's post
Carcass wrote:
Quantity A
Quantity B
x + 32y
32x + y


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


We can solve this question using matching operations

Given:
Quantity A: x + 32y
Quantity B: 32x + y

Subtract x from both quantities to get:
Quantity A: 32y
Quantity B: 31x + y

Subtract y from both quantities to get:
Quantity A: 31y
Quantity B: 31x

Divide both quantities by 31 to get:
Quantity A: y
Quantity B: x

Since we have no information about x and y, there's no way to determine which value is greater.

Answer: D

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Intern
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Kudos [?]: 31 [0], given: 30

Re: x + 32Y [#permalink] New post 02 Jan 2020, 21:14
Just input numbers here.
If both x and y = 1 then the both sides are equal so, in this case ans is C.
But if x = 1 and y = 2 then the Left side is 65 and the right side is 34, in this case ans is A.
So the correct ans is D
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Posts: 187
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Kudos [?]: 189 [0], given: 5

Re: x + 32Y [#permalink] New post 02 Jan 2020, 22:17
We can subtract either x or y from both sides.
Let's subtract y from both sides.

Quantity A - x + 31y
Quantity B - 32x

Now, put values, if x = y = 1
Quantity A = Quantity B

if x = 1, y = 2
Quantity A > Quantity B

We can see that the quantities are dependent on the values of x and y and without those values we cannot determine which quantity is bigger.

Hence, D

Carcass wrote:
Quantity A
Quantity B
x + 32y
32x + y


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

_________________

If you like my solution, do give kudos!

Re: x + 32Y   [#permalink] 02 Jan 2020, 22:17
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