Carcass wrote:
(x + 3)(y − 4) = 0
Quantity A |
Quantity B |
xy |
−12 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Given: (x + 3)(y − 4) = 0
This tells us that EITHER x = -3 OR y = 4
So, for example, if x = -3 and y = ANY number, the equation (x + 3)(y − 4) = 0 holds true.
So, one possible solution to the equation (x + 3)(y − 4) = 0 is x = -3 and y = 0
We get:
QUANTITY A: xy = (-3)(0) = 0
QUANTITY B: -12
In this case QUANTITY A is greater
Another possible solution to the equation (x + 3)(y − 4) = 0 is x = -11 and y = 4
We get:
QUANTITY A: xy = (-11)(4) = -44
QUANTITY B: -12
In this case QUANTITY B is greater
Another possible solution to the equation (x + 3)(y − 4) = 0 is x = -3 and y = 4
We get:
QUANTITY A: xy = (-3)(4) = -12
QUANTITY B: -12
In this case QUANTITY A = QUANTITY B
Answer: D
Cheers,
Brent
_________________
Brent Hanneson – Creator of greenlighttestprep.com
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