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Moderator  Joined: 18 Apr 2015
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x^2 + x - 40 = 0 [#permalink]
Expert's post 00:00

Question Stats: 59% (01:20) correct 40% (01:47) wrong based on 27 sessions

$$x^2 + x - 40 = 0$$

 Quantity A Quantity B | x + 1| 5

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

_________________ Director Joined: 03 Sep 2017
Posts: 521
Followers: 1

Kudos [?]: 344  , given: 66

Re: x^2 + x - 40 = 0 [#permalink]
2
KUDOS
The solutions to the equations are $$\frac{-1\pm \sqrt161}{2}$$, then given that $$sqrt161>12$$, the two roots are both positive numbers. Thus, when they are summed to 1 and taken absolute value they keep being positive and greater than 5 in both the occasions.

Thus answer is A
Intern Joined: 11 Jan 2018
Posts: 44
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Kudos [?]: 33 , given: 7

Re: x^2 + x - 40 = 0 [#permalink]
IlCreatore wrote:
The solutions to the equations are $$\frac{-1\pm \sqrt161}{2}$$, then given that $$sqrt161>12$$, the two roots are both positive numbers. Thus, when they are summed to 1 and taken absolute value they keep being positive and greater than 5 in both the occasions.

Thus answer is A

Another good explanation,
Giving you 1 more kudos.
It was a good question.
Yes, in both scenarios, Quantity A always greater.
So Choice A.
_________________

Persistence >>>>>>> Success

Don't say thanks, just give KUDOS.
1 kudos = 1000 Thanks Re: x^2 + x - 40 = 0   [#permalink] 28 Feb 2018, 14:18
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