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# x > 1

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Joined: 18 Apr 2015
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x > 1 [#permalink]  05 Jun 2019, 08:53
Expert's post
00:00

Question Stats:

83% (00:34) correct 16% (00:24) wrong based on 12 sessions
$$x > 1$$

 Quantity A Quantity B $$(x+5)(2x+3)$$ $$(x+3)(2x+5)$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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GRE Instructor
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Kudos [?]: 2190 [0], given: 26

Re: x > 1 [#permalink]  05 Jun 2019, 09:20
Expert's post
Carcass wrote:
$$x > 1$$

 Quantity A Quantity B $$(x+5)(2x+3)$$ $$(x+3)(2x+5)$$

Given:
Quantity A: $$(x+5)(2x+3)$$
Quantity B: $$(x+3)(2x+5)$$

Use the F.O.I.L. method to expand (and simplify) the two quantities:
Quantity A: $$2x^2+13x+15$$
Quantity B: $$2x^2+11x+15$$

From here, we can solve this question using matching operations

Subtract $$2x^2$$from two quantities to get:
Quantity A: $$13x+15$$
Quantity B: $$11x+15$$

Subtract $$15$$ from two quantities to get:
Quantity A: $$13x$$
Quantity B: $$11x$$

Since x is POSITIVE, we can safely divide both quantities by x to get:
Quantity A: $$13$$
Quantity B: $$11$$

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Re: x > 1   [#permalink] 05 Jun 2019, 09:20
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