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# x > 0

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Founder
Joined: 18 Apr 2015
Posts: 6211
Followers: 99

Kudos [?]: 1199 [0], given: 5721

x > 0 [#permalink]  18 Sep 2018, 10:27
Expert's post
00:00

Question Stats:

72% (00:21) correct 27% (00:07) wrong based on 22 sessions

$$x > 0$$

 Quantity A Quantity B $$x^3 + 1$$ $$x^4 + 1$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

_________________
GRE Instructor
Joined: 10 Apr 2015
Posts: 1652
Followers: 57

Kudos [?]: 1577 [1] , given: 8

Re: x > 0 [#permalink]  18 Sep 2018, 15:49
1
KUDOS
Expert's post
Carcass wrote:
$$x > 0$$

 Quantity A Quantity B $$x^3 + 1$$ $$x^4 + 1$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

We can solve this question using matching operations

Given:
Quantity A: x^3 + 1
Quantity B: x^4 + 1

Subtract 1 from both quantities to get:
Quantity A: x^3
Quantity B: x^4

Since x is POSITIVE, we know that x^3 is POSITIVE.
So, we can safely divide both quantities by x^3 to get:
Quantity A: 1
Quantity B: x

We know that x > 0.
This means x COULD equal 8, in which case, Quantity B is greater
Or x COULD equal 0.5, in which case, Quantity A is greater
x COULD also equal 1, in which case, the quantities are equal

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Re: x > 0   [#permalink] 18 Sep 2018, 15:49
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