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x > 0 [#permalink] New post 18 Sep 2018, 10:27
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Question Stats:

71% (00:20) correct 28% (00:00) wrong based on 14 sessions
\(x > 0\)

Quantity A
Quantity B
\(x^3 + 1\)
\(x^4 + 1\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: x > 0 [#permalink] New post 18 Sep 2018, 15:49
Expert's post
Carcass wrote:
\(x > 0\)

Quantity A
Quantity B
\(x^3 + 1\)
\(x^4 + 1\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


We can solve this question using matching operations

Given:
Quantity A: x^3 + 1
Quantity B: x^4 + 1

Subtract 1 from both quantities to get:
Quantity A: x^3
Quantity B: x^4

Since x is POSITIVE, we know that x^3 is POSITIVE.
So, we can safely divide both quantities by x^3 to get:
Quantity A: 1
Quantity B: x

We know that x > 0.
This means x COULD equal 8, in which case, Quantity B is greater
Or x COULD equal 0.5, in which case, Quantity A is greater
x COULD also equal 1, in which case, the quantities are equal

Answer: D

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Re: x > 0   [#permalink] 18 Sep 2018, 15:49
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