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Founder
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x > 0 [#permalink] New post 18 Sep 2018, 10:25
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Question Stats:

74% (00:15) correct 25% (00:07) wrong based on 43 sessions


\(x > 0\)

Quantity A
Quantity B
\(\frac{1}{2x}\)
\(2x\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: x > 0 [#permalink] New post 18 Sep 2018, 21:07
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since x is a +ve number multiply both quantities by 2x to get Qty A \(=1\) and Qty B = \(4x^2\)
Divide both sides by 4 to get Qty A = \(\frac{1}{4}\) and Qty B = \(x^2\)

Since x can be any positive number such as \(0.5\) or \(7\)
when x = \(0.5\) qty A =Qty B but when \(x=7\) Qty A < Qty B
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Re: x > 0 [#permalink] New post 05 Oct 2018, 06:23
D is the answer
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Re: x > 0 [#permalink] New post 05 Oct 2018, 07:00
Expert's post
[quote="Carcass"]\(x > 0\)

Quantity A
Quantity B
\(\frac{1}{2x}\)
\(2x\)



We can solve this question using matching operations

Given:
Quantity A: \(\frac{1}{2x}\)
Quantity B: 2x

Since x is POSITIVE, we know that 2x is POSITIVE, so we can safely multiply both quantities by 2x to get:
Quantity A: 1
Quantity B: 4x²

Now let's test some values of x

If x = 2, then we get:
Quantity A: 1
Quantity B: 4(2²) = 4(4) = 16
In this case, Quantity B is greater

If x = 0.5, then we get:
Quantity A: 1
Quantity B: 4(0.5²) = 4(0.25) = 1
In this case, the quantities are equal

Answer: D

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Re: x > 0   [#permalink] 05 Oct 2018, 07:00
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