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# x > 0

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Moderator
Joined: 18 Apr 2015
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x > 0 [#permalink]  18 Sep 2018, 10:25
Expert's post
00:00

Question Stats:

77% (00:14) correct 22% (00:06) wrong based on 31 sessions
$$x > 0$$

 Quantity A Quantity B $$\frac{1}{2x}$$ $$2x$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Director
Joined: 07 Jan 2018
Posts: 553
Followers: 4

Kudos [?]: 477 [0], given: 84

Re: x > 0 [#permalink]  18 Sep 2018, 21:07
since x is a +ve number multiply both quantities by 2x to get Qty A $$=1$$ and Qty B = $$4x^2$$
Divide both sides by 4 to get Qty A = $$\frac{1}{4}$$ and Qty B = $$x^2$$

Since x can be any positive number such as $$0.5$$ or $$7$$
when x = $$0.5$$ qty A =Qty B but when $$x=7$$ Qty A < Qty B
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This is my response to the question and may be incorrect. Feel free to rectify any mistakes

Intern
Joined: 06 Jul 2018
Posts: 32
Followers: 0

Kudos [?]: 1 [0], given: 3

Re: x > 0 [#permalink]  05 Oct 2018, 06:23
GRE Instructor
Joined: 10 Apr 2015
Posts: 1232
Followers: 45

Kudos [?]: 1113 [0], given: 7

Re: x > 0 [#permalink]  05 Oct 2018, 07:00
Expert's post
[quote="Carcass"]$$x > 0$$

 Quantity A Quantity B $$\frac{1}{2x}$$ $$2x$$

We can solve this question using matching operations

Given:
Quantity A: $$\frac{1}{2x}$$
Quantity B: 2x

Since x is POSITIVE, we know that 2x is POSITIVE, so we can safely multiply both quantities by 2x to get:
Quantity A: 1
Quantity B: 4x²

Now let's test some values of x

If x = 2, then we get:
Quantity A: 1
Quantity B: 4(2²) = 4(4) = 16
In this case, Quantity B is greater

If x = 0.5, then we get:
Quantity A: 1
Quantity B: 4(0.5²) = 4(0.25) = 1
In this case, the quantities are equal

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Re: x > 0   [#permalink] 05 Oct 2018, 07:00
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