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# |–x| ≥ 6

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Moderator
Joined: 18 Apr 2015
Posts: 5888
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Kudos [?]: 1154 [0], given: 5471

|–x| ≥ 6 [#permalink]  23 Jul 2018, 10:36
Expert's post
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Question Stats:

57% (00:51) correct 42% (00:43) wrong based on 52 sessions
$$|–x | \geq 6$$

$$x * y^2 < 0$$ and y is an integer.

 Quantity A Quantity B x - 4

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E
[Reveal] Spoiler: OA

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Director
Joined: 07 Jan 2018
Posts: 604
Followers: 7

Kudos [?]: 544 [1] , given: 88

Re: |–x| ≥ 6 [#permalink]  28 Jul 2018, 01:00
1
KUDOS
we can find the value of x;
either -x => 6
hence, x <= -6

or, -x <= -6
hence, x => 6

from the second eqn we know that y^2 has to be +ve. Therefore x is -ve, therefore x has to be less than -6
Therefore B is greater

Carcass I cannot send msg, nor use the preview tool in the text box instead on pressing the button I get the color choice option
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Intern
Joined: 10 Oct 2017
Posts: 10
Followers: 0

Kudos [?]: 3 [1] , given: 0

Re: |–x| ≥ 6 [#permalink]  27 Sep 2018, 22:36
1
KUDOS
x∗y2<0x∗y2<0 and y is an integer

why was this given? how is this helping us solve the question? Why is statement one not enough
Director
Joined: 07 Jan 2018
Posts: 604
Followers: 7

Kudos [?]: 544 [1] , given: 88

Re: |–x| ≥ 6 [#permalink]  28 Sep 2018, 02:34
1
KUDOS
1st statement is enough to ans the question. The 1st statement alone gives ans D as x can be less than -6 or more than 6 however since we are also given with 2nd statement x can be only less than -6.
We have to take into account all the informtion given prior to the quantities we are comparing.

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Re: |–x| ≥ 6   [#permalink] 28 Sep 2018, 02:34
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