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|–x| ≥ 6

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|–x| ≥ 6 [#permalink] New post 23 Jul 2018, 10:36
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Question Stats:

70% (00:45) correct 29% (00:47) wrong based on 123 sessions
\(|–x | \geq 6\)

\(x * y^2 < 0\) and y is an integer.

Quantity A
Quantity B
x
- 4


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

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[Reveal] Spoiler: OA

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Re: |–x| ≥ 6 [#permalink] New post 28 Jul 2018, 01:00
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we can find the value of x;
either -x => 6
hence, x <= -6

or, -x <= -6
hence, x => 6

from the second eqn we know that y^2 has to be +ve. Therefore x is -ve, therefore x has to be less than -6
Therefore B is greater

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Re: |–x| ≥ 6 [#permalink] New post 27 Sep 2018, 22:36
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x∗y2<0x∗y2<0 and y is an integer

why was this given? how is this helping us solve the question? Why is statement one not enough
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Re: |–x| ≥ 6 [#permalink] New post 28 Sep 2018, 02:34
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1st statement is enough to ans the question. The 1st statement alone gives ans D as x can be less than -6 or more than 6 however since we are also given with 2nd statement x can be only less than -6.
We have to take into account all the informtion given prior to the quantities we are comparing.

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Re: |–x| ≥ 6 [#permalink] New post 18 Sep 2020, 02:33
Since x*y^2 < 0 and y is an integer,

Since y^2 > 0,
x < 0

And based on |-x| >= 6, we can see that x <-6, therefore B is the answer.
Re: |–x| ≥ 6   [#permalink] 18 Sep 2020, 02:33
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