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x > 0 > y

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GRE 1: Q167 V156
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x > 0 > y [#permalink] New post 30 Aug 2018, 16:29
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Question Stats:

66% (01:02) correct 33% (00:40) wrong based on 18 sessions
\(x > 0 > y\)

Quantity A
Quantity B
\(x - y\)
\((x + y)^{2}\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Sandy
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Kudos [?]: 1131 [0], given: 7

Re: x > 0 > y [#permalink] New post 31 Aug 2018, 09:13
Expert's post
sandy wrote:
\(x > 0 > y\)

Quantity A
Quantity B
\(x - y\)
\((x + y)^{2}\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


I can't think of any useful algebraic manipulations that will help me, so let's test some possible cases...

ASIDE: The given information tells us that x is POSITIVE and y is NEGATIVE

Case 1: x = 1 and y = -1
We get:
QUANTITY A: x - y = 1 - (-1) = 2
QUANTITY B: (x + y)² = (1 + -1)² = 0² = 0
In this case, Quantity A is greater

Case 2: x = 10 and y = -1
We get:
QUANTITY A: x - y = 10 - (-1) = 11
QUANTITY B: (x + y)² = (10 + -1)² = 9² = 81
In this case, Quantity B is greater

Answer: D

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com
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Posts: 190
Location: United States
GRE 1: Q142 V146
WE: Information Technology (Computer Software)
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Kudos [?]: 77 [0], given: 99

Re: x > 0 > y [#permalink] New post 01 Sep 2018, 07:11
GreenlightTestPrep wrote:
sandy wrote:
\(x > 0 > y\)

Quantity A
Quantity B
\(x - y\)
\((x + y)^{2}\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


I can't think of any useful algebraic manipulations that will help me, so let's test some possible cases...

ASIDE: The given information tells us that x is POSITIVE and y is NEGATIVE

Case 1: x = 1 and y = -1
We get:
QUANTITY A: x - y = 1 - (-1) = 2
QUANTITY B: (x + y)² = (1 + -1)² = 0² = 0
In this case, Quantity A is greater

Case 2: x = 10 and y = -1
We get:
QUANTITY A: x - y = 10 - (-1) = 11
QUANTITY B: (x + y)² = (10 + -1)² = 9² = 81
In this case, Quantity B is greater

Answer: D

Cheers,
Brent


I expanded option B and equated to A(LHS) and the LHS went 0 and then the whole equation stopped making sense and chooce D.

I am wondering why did you not expanded x+y whole square equation?
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Kudos [?]: 1131 [0], given: 7

Re: x > 0 > y [#permalink] New post 03 Sep 2018, 05:26
Expert's post
[/quote]

I expanded option B and equated to A(LHS) and the LHS went 0 and then the whole equation stopped making sense and chooce D.

I am wondering why did you not expanded x+y whole square equation?[/quote]

Let's see what happens if we expand

Given:
QUANTITY A: x - y
QUANTITY B: (x + y)²

Expand Quantity B to get:
QUANTITY A: x - y
QUANTITY B: x² + 2xy + y²

Now what can we do?

Whatever we do from here seems more likely to make matters more confusing.
For example, we COULD add y to both quantities to get:
QUANTITY A: x
QUANTITY B: x² + 2xy + y + y²
This doesn't help.

What if we subtract x from both quantities? We get:
QUANTITY A: 0
QUANTITY B: x² + 2xy + y - x + y²
Yikes!!

At this point, we should probably start considering a different approach.

Cheers,
Brent
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Re: x > 0 > y   [#permalink] 03 Sep 2018, 05:26
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