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Williams has x eggs. He sells y of them at a profit of 10 pe [#permalink]
29 Apr 2019, 02:25
Question Stats:
48% (01:19) correct
51% (02:04) wrong based on 33 sessions
Williams has x eggs. He sells y of them at a profit of 10 percent and the remaining eggs at a loss of 10 percent. He made a profit overall.
Quantity A 
Quantity B 
xy 
y 
A)The quantity in Column A is greater. B)The quantity in Column B is greater. C)The two quantities are equal. D)The relationship cannot be determined from the information given.
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Re: Williams has x eggs. He sells y of them at a profit of 10 pe [#permalink]
16 May 2019, 04:54
Hi,
The answer is (D).
First, mentally, assume the cost price of 1 egg to be 'k'. Williams first sells 'y' eggs at 10% profit, which means yk*1.1. Second, he sells the remaining eggs at a loss of 10%, which means k(xy)*0.9.
Now, it is mentioned that he made a profit, and this is where you need to catch that without the values of 'x' and 'y', it is impossible to determine the greater value between '(xy)' and 'y'.
For instance, if (xy)=y, then it is still a profit of 20%, as mentioned in the question. However, if (xy)<y, even then, there is a profit.
Take an assumption to understand this.
x=10 y=6 Cost Price per egg = $100
Therefore, the Selling Price for 6 eggs is 100*1.1*6 = 660.
xy=4, therefore selling price for 4 eggs is 100*0.9*4 = 360. Therefore, the overall profit is 660+360200=820.
But if xy=y, then Selling Price 1 for 5 eggs is 100*1.1*5=550, and Selling Price 2 is 100*0.9*5=450. Therefore, overall profit is 1000200=800.
Therefore, in both cases, we find that Williams makes an overall profit. The moment there are two equally plausible cases, the answer becomes unverifiable, and is therefore (D).



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Re: Williams has x eggs. He sells y of them at a profit of 10 pe [#permalink]
30 Jul 2019, 07:18
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Answer is B. if x and y were same then there would be no profit or loss. But here is get profit so Y>x. Quantity A something negative. Answer is B



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Re: Williams has x eggs. He sells y of them at a profit of 10 pe [#permalink]
30 Jul 2019, 17:05
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Answer is B.
X = # of eggs Y = # of eggs sold X  Y = # of eggs NOT sold
Since he made a profit: Y > X  Y, therefore B must be greater than A



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Re: Williams has x eggs. He sells y of them at a profit of 10 pe [#permalink]
31 Jul 2019, 07:23
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grewhiz wrote: Hi,
The answer is (D).
First, mentally, assume the cost price of 1 egg to be 'k'. Williams first sells 'y' eggs at 10% profit, which means yk*1.1. Second, he sells the remaining eggs at a loss of 10%, which means k(xy)*0.9.
Now, it is mentioned that he made a profit, and this is where you need to catch that without the values of 'x' and 'y', it is impossible to determine the greater value between '(xy)' and 'y'.
For instance, if (xy)=y, then it is still a profit of 20%, as mentioned in the question. However, if (xy)<y, even then, there is a profit.
Take an assumption to understand this.
x=10 y=6 Cost Price per egg = $100
Therefore, the Selling Price for 6 eggs is 100*1.1*6 = 660.
xy=4, therefore selling price for 4 eggs is 100*0.9*4 = 360. Therefore, the overall profit is 660+360200=820.
But if xy=y, then Selling Price 1 for 5 eggs is 100*1.1*5=550, and Selling Price 2 is 100*0.9*5=450. Therefore, overall profit is 1000200=800.
Therefore, in both cases, we find that Williams makes an overall profit. The moment there are two equally plausible cases, the answer becomes unverifiable, and is therefore (D). Please review the calculations, Answer is (B)



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Re: Williams has x eggs. He sells y of them at a profit of 10 pe [#permalink]
01 Aug 2019, 13:56
As he is always making profit y will be more than 50% of x so the answer will be always b



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Re: Williams has x eggs. He sells y of them at a profit of 10 pe [#permalink]
02 Aug 2019, 11:05
Y eggs value = p(y) x 1.1 Rest Eggs value = P(xy) x 0.9
p(y) x 1.1 + P(xy) x 0.9 > p(x)
above equation defined due to profit mentioned
leads to 0.2y > x0.9x 0.2y > 0.1x 2y > x y > x/2
using this condition answer will be "B"




Re: Williams has x eggs. He sells y of them at a profit of 10 pe
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02 Aug 2019, 11:05





