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Williams has x eggs. He sells y of them at a profit of 10 pe

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Williams has x eggs. He sells y of them at a profit of 10 pe [#permalink] New post 29 Apr 2019, 02:25
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83% (01:14) correct 16% (00:32) wrong based on 6 sessions
Williams has x eggs. He sells y of them at a profit of 10 percent and the remaining eggs at a loss of 10 percent. He made a profit overall.

Quantity A
Quantity B
x-y
y


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: Williams has x eggs. He sells y of them at a profit of 10 pe [#permalink] New post 16 May 2019, 04:54
Hi,

The answer is (D).

First, mentally, assume the cost price of 1 egg to be 'k'. Williams first sells 'y' eggs at 10% profit, which means yk*1.1.
Second, he sells the remaining eggs at a loss of 10%, which means k(x-y)*0.9.

Now, it is mentioned that he made a profit, and this is where you need to catch that without the values of 'x' and 'y', it is impossible to determine the greater value between '(x-y)' and 'y'.

For instance, if (x-y)=y, then it is still a profit of 20%, as mentioned in the question. However, if (x-y)<y, even then, there is a profit.

Take an assumption to understand this.

x=10
y=6
Cost Price per egg = $100

Therefore, the Selling Price for 6 eggs is 100*1.1*6 = 660.

x-y=4, therefore selling price for 4 eggs is 100*0.9*4 = 360. Therefore, the overall profit is 660+360-200=820.

But if x-y=y, then Selling Price 1 for 5 eggs is 100*1.1*5=550, and Selling Price 2 is 100*0.9*5=450. Therefore, overall profit is 1000-200=800.

Therefore, in both cases, we find that Williams makes an overall profit. The moment there are two equally plausible cases, the answer becomes unverifiable, and is therefore (D).
Re: Williams has x eggs. He sells y of them at a profit of 10 pe   [#permalink] 16 May 2019, 04:54
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Williams has x eggs. He sells y of them at a profit of 10 pe

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