Carcass wrote:
If \(\frac{x+2}{y-3}=0\), which of the following must be true?
(A) x = 2 and y = 3
(B) x= 2 and \(y \neq 3\)
(C) x = 0 and y = 0
(D) x = -2 and y = 3
(E) x = -2 and \(y \neq 3\)
In order for (x+2)/(y-3) = 0, it must be the case that the numerator, x+2, is equal to zero.
If x + 2 = 0, then x = -2
Check the answer choices.....
We can ELIMINATE A, B and C, but are still left with D and E
IMPORTANT: 0/0 does NOT equal zero.
This means, for (x+2)/(y-3) to equal 0,
the denominator CANNOT equal 0In other words, y-3 CANNOT equal 0
So, y CANNOT equal 3
Answer: E
Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com
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