98^1 = 98
98^2 = (98)(98) = ---4 [note: we need only recognize that the units digit of 98^2 will be equal to the units digit of (8)(8), which is 4]
98^3 = (98)(98)(98) = (---4)(98) = ----2 [note: we need only recognize that the units digit of (---4)(98) will be equal to the units digit of (4)(8), which is 2]
98^4 = (98)(98)(98)(98) = (----2)(98) = ----6
98^5 = (98)(98)(98)(98)(98) = (----6)(98) = ----8

At this point, we are repeating the pattern. So, there's no need to continue.
The pattern of units digits will be 8, 4, 2, 6, 8, 4, 2, 6, 8, etc

Answer: 2, 4, 6, 8 (C, E, G, I)

Cheers,
Brent
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Honestly,

I do not think such question adhere to the standards..........

YES, But it is the better one for clarifying the unit digit conception.
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\(8\) has a repeating pattern of \(4\)

\(8^1 = 8\)
\(8^2 = 64\)
\(8^3 = 512\)
\(8^4 = 4,096\)
\(8^5 = 32,768\)

i.e. 8, 4, 2, and 6 repeat at the units place every 4 powers

Hence, C, E, G, and I
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