Carcass wrote:

Attachment:

The attachment **xy.jpg** is no longer available

Which of the following could be the equation of the graph in the xy-plane shown above?

A. \(y = x^2 + x - 60\)

B. \(y = x^2 + x - 20\)

C. \(y = x^2 + 3x - 60\)

D. \(y = 3x^2 + x - 60\)

E. \(y = 3x^2 + 3x - 60\)

Here we have to use the vertex formula which is-

\(y = a(x-h)^2 + k\)

here h= vertex

From the graph k = -60 and h almost equal to -1

SO we need a equation as

y= (x-(-1)) -60

or y = (x + 1) -60

Only equation E have the same presentation

because \(y = 3x^2 +3x -60\)

or it can be written y = 3x(x + 1) - 60

Attachments

xy.jpg [ 12.87 KiB | Viewed 2626 times ]

_________________

If you found this post useful, please let me know by pressing the Kudos Button

Rules for Posting https://greprepclub.com/forum/rules-for ... -1083.html