Lazy Logic:

Substitute 0
(x-2)(x-5)(x+9) = 90 && (x+1)(x-4)(x-2) = 8
A is greater

Substitute 5
(x-2)(x-5)(x+9) = 0 && (x+1)(x-4)(x-2) = 18
B is greater

Since no condition exists to constrain the value of x, the answer is
D. The relationship cannot be determined from the information given

Kudos if it was helpful

Let's simplify while assuming first (x-2) positive:

We can divided by x-2 both quantities, thereby we'll get

Quantity A: (x-5)(x+9)
Quantity B: (x+1)(x-4)

Let's multiply,

Quantity A: \(x^2\) + 4x - 45
Quantity B: \(x^2\) - 3x + 4

After subtracting \(x^2\) from both quantities and then simplifying,

Quantity A: 7x
Quantity B: 41

As we don't know what is x, so it's just CANNOT BE DETERMINE FROM THE INFORMATION GIVEN.

Also, if we assume (x-2) negative, we'll come up with same situation.

Thus, Choice D correct.
_________________

Substitute 0
(x-2)(x-5)(x+9) = 90 && (x+1)(x-4)(x-2) = 8
A is greater

Substitute 5
(x-2)(x-5)(x+9) = 0 && (x+1)(x-4)(x-2) = 18
B is greater