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Which is greater \sqrt38 + \sqrt45 or 12

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Which is greater \sqrt38 + \sqrt45 or 12 [#permalink] New post 27 Feb 2019, 00:46
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Question Stats:

93% (00:13) correct 6% (00:09) wrong based on 16 sessions
Quantity A
Quantity B
\(\sqrt{38}\) + \(\sqrt{45}\)
12


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: Which is greater \sqrt38 + \sqrt45 or 12 [#permalink] New post 09 Mar 2019, 11:49
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\(\sqrt{36}\) = 6

Hence, both \(\sqrt{38}\) and \(\sqrt{45}\) are greater than 6. This means that \(\sqrt{38}\) + \(\sqrt{45}\) is greater than 12.
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Re: Which is greater \sqrt38 + \sqrt45 or 12 [#permalink] New post 14 May 2019, 08:44
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Carcass wrote:
Quantity A
Quantity B
\(\sqrt{38}\) + \(\sqrt{45}\)
12


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


We know that:
√36 = 6
√49 = 7

Since 38 is BETWEEN 36 and 49, we know that √38 must be BETWEEN 6 and 7
So, we can say √38 = 6.something

Likewise, since 45 is BETWEEN 36 and 49, we know that √45 must be BETWEEN 6 and 7
So, we can say √45 = 6.something

We get:
QUANTITY A: 6.something + 6.something
QUANTITY B: 12

Quantity A is greater.

Answer: A

Cheers,
Brent
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Re: Which is greater \sqrt38 + \sqrt45 or 12   [#permalink] 14 May 2019, 08:44
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