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Senior Manager Joined: 20 May 2014
Posts: 282
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Which is greater? [#permalink] 00:00

Question Stats: 20% (01:21) correct 80% (01:09) wrong based on 15 sessions  A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

Kudos for correct solution.

[Reveal] Spoiler:
Attachment: gqgpp_img11.png [ 627 Bytes | Viewed 897 times ]

Attachment: gqgpp_img12.png [ 1.32 KiB | Viewed 889 times ]
[Reveal] Spoiler: OA
Manager Joined: 27 Sep 2017
Posts: 112
Followers: 1

Kudos [?]: 30 , given: 4

Re: Which is greater? [#permalink]
Bunuel wrote:  A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

Kudos for correct solution.

[Reveal] Spoiler:
Attachment:
gqgpp_img11.png

Attachment:
gqgpp_img12.png

Don't know how it works; can anyone give explanation? Director Joined: 03 Sep 2017
Posts: 521
Followers: 1

Kudos [?]: 344  , given: 66

Re: Which is greater? [#permalink]
1
KUDOS
Let's start from the fact that $$\frac{AB}{AC}=\frac{AC}{BC}$$, then given AB = AC+BC, we can rewrite the equality as $$\frac{AC+BC}{AC}=1+\frac{BC}{AC}=\frac{AC}{BC}$$. Then, given that BC is smaller than AC, BC/AC is smaller than 1 so that summed to 1 is surely less than 3. Quantity B is greater. Manager Joined: 27 Sep 2017
Posts: 112
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Kudos [?]: 30  , given: 4

Re: Which is greater? [#permalink]
1
KUDOS
IlCreatore wrote:
Let's start from the fact that $$\frac{AB}{AC}=\frac{AC}{BC}$$, then given AB = AC+BC, we can rewrite the equality as $$\frac{AC+BC}{AC}=1+\frac{BC}{AC}=\frac{AC}{BC}$$. Then, given that BC is smaller than AC, BC/AC is smaller than 1 so that summed to 1 is surely less than 3. Quantity B is greater.

thank you for the info: but how do you make sure that BC is smaller than AC given that the picture might not be drawn to scale?
Manager Joined: 03 Dec 2017
Posts: 65
Followers: 0

Kudos [?]: 16 , given: 20

Re: Which is greater? [#permalink]
IlCreatore wrote:
Let's start from the fact that $$\frac{AB}{AC}=\frac{AC}{BC}$$, then given AB = AC+BC, we can rewrite the equality as $$\frac{AC+BC}{AC}=1+\frac{BC}{AC}=\frac{AC}{BC}$$. Then, given that BC is smaller than AC, BC/AC is smaller than 1 so that summed to 1 is surely less than 3. Quantity B is greater.

how do you get the part 1+\frac{BC}{AC} ? Director Joined: 20 Apr 2016
Posts: 826
WE: Engineering (Energy and Utilities)
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Kudos [?]: 603  , given: 124

Re: Which is greater? [#permalink]
2
KUDOS
Peter wrote:
IlCreatore wrote:
Let's start from the fact that $$\frac{AB}{AC}=\frac{AC}{BC}$$, then given AB = AC+BC, we can rewrite the equality as $$\frac{AC+BC}{AC}=1+\frac{BC}{AC}=\frac{AC}{BC}$$. Then, given that BC is smaller than AC, BC/AC is smaller than 1 so that summed to 1 is surely less than 3. Quantity B is greater.

thank you for the info: but how do you make sure that BC is smaller than AC given that the picture might not be drawn to scale?

Good question,

But you can try putting the some values,

But remember it should satisfy the equation $$\frac{AB}{AC}=\frac{AC}{BC}$$

Let AB =12
AC= 6
BC = 3

These values satisfy the above equation , and $$\frac{AC}{BC}= 2$$ which is less than 3
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Rules for Posting https://greprepclub.com/forum/rules-for ... -1083.html Director Joined: 20 Apr 2016
Posts: 826
WE: Engineering (Energy and Utilities)
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Kudos [?]: 603  , given: 124

Re: Which is greater? [#permalink]
2
KUDOS
wongpcla wrote:
IlCreatore wrote:
Let's start from the fact that $$\frac{AB}{AC}=\frac{AC}{BC}$$, then given AB = AC+BC, we can rewrite the equality as $$\frac{AC+BC}{AC}=1+\frac{BC}{AC}=\frac{AC}{BC}$$. Then, given that BC is smaller than AC, BC/AC is smaller than 1 so that summed to 1 is surely less than 3. Quantity B is greater.

how do you get the part 1+\frac{BC}{AC} ?

Because AB = AC + BC

Now
$$\frac{AB}{AC}$$ can be written as

$$\frac{(AC +BC)}{AC} = \frac{AC}{AC} + \frac{BC}{AC}$$

= $$1 + \frac{BC}{AC}$$
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Rules for Posting https://greprepclub.com/forum/rules-for ... -1083.html Director  Joined: 07 Jan 2018
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Kudos [?]: 544  , given: 88

Re: Which is greater? [#permalink]
1
KUDOS
pranab01 wrote:
Peter wrote:
IlCreatore wrote:
Let's start from the fact that $$\frac{AB}{AC}=\frac{AC}{BC}$$, then given AB = AC+BC, we can rewrite the equality as $$\frac{AC+BC}{AC}=1+\frac{BC}{AC}=\frac{AC}{BC}$$. Then, given that BC is smaller than AC, BC/AC is smaller than 1 so that summed to 1 is surely less than 3. Quantity B is greater.

thank you for the info: but how do you make sure that BC is smaller than AC given that the picture might not be drawn to scale?

Good question,

But you can try putting the some values,

But remember it should satisfy the equation $$\frac{AB}{AC}=\frac{AC}{BC}$$

Let AB =12
AC= 6
BC = 3

These values satisfy the above equation , and $$\frac{AC}{BC}= 2$$ which is less than 3

I think if AB=12 and AC = 6 then BC must equal to 6 and not 3 as BC = AB-AC
_________________

This is my response to the question and may be incorrect. Feel free to rectify any mistakes

Intern Joined: 18 May 2016
Posts: 35
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Kudos [?]: 15 , given: 13

Re: Which is greater? [#permalink]
Peter wrote:
IlCreatore wrote:
Let's start from the fact that $$\frac{AB}{AC}=\frac{AC}{BC}$$, then given AB = AC+BC, we can rewrite the equality as $$\frac{AC+BC}{AC}=1+\frac{BC}{AC}=\frac{AC}{BC}$$. Then, given that BC is smaller than AC, BC/AC is smaller than 1 so that summed to 1 is surely less than 3. Quantity B is greater.

thank you for the info: but how do you make sure that BC is smaller than AC given that the picture might not be drawn to scale?

BC must be smaller, otherwise the equation in the question cannot hold.
Try to plug in numbers (with BC > AC) and you'll see  Re: Which is greater?   [#permalink] 24 Jan 2018, 10:44
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