 It is currently 15 Jun 2019, 21:54 GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here. Which is greater?  Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:
Senior Manager Joined: 20 May 2014
Posts: 282
Followers: 18

Kudos [?]: 50 , given: 220 00:00

Question Stats: 50% (01:02) correct 50% (00:34) wrong based on 10 sessions  A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

Kudos for correct solution.

[Reveal] Spoiler:
Attachment: gqgpp_img3.png [ 6.58 KiB | Viewed 1074 times ]

Attachment: AAAA-QC-for-circle.jpg [ 3.6 KiB | Viewed 1069 times ]
[Reveal] Spoiler: OA Director Joined: 03 Sep 2017
Posts: 520
Followers: 1

Kudos [?]: 356  , given: 66

2
KUDOS
Since triangle ABC is built on the diameter of the circle, the angle in C is 90°. Thus we can use the Pythagorean theorem to get side AC as $$AB^2-BC^2 = 16-9 = 7$$ so that Ac is equal to $$\sqrt7$$. Then, the area of the square ACDE is $$AC^2 = 7$$

Manager Joined: 03 Dec 2017
Posts: 65
Followers: 0

Kudos [?]: 16 , given: 20

Bunuel please correct how wrong I am,
OB=2, OC=2, BC=3 ; OA=2, OC=2, AC=3 similar triangle AOC~BOC
AC*AC = 3*3 = 9
Senior Manager Joined: 20 May 2014
Posts: 282
Followers: 18

Kudos [?]: 50 , given: 220

wongpcla wrote:  A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

Bunuel please correct how wrong I am,
OB=2, OC=2, BC=3 ; OA=2, OC=2, AC=3 similar triangle AOC~BOC
AC*AC = 3*3 = 9

No. Triangles AOC and BOC are not similar. Only two side there are equal. To find AC you shoul recall the following property:

A right triangle inscribed in a circle must have its hypotenuse as the diameter of the circle (the reverse is also true: if the diameter of a circle is also the triangle’s side, then that triangle is a right triangle).

Thus, ABC is a right tringle right angled at C. Now, using Pythagoras theorem:
AC^2 + BC^2 = AB^2;
AC^2 + 9 = 16;
$$AC =\sqrt{7}$$

The area of the square $$side^2=(\sqrt{7})^2=7$$.

The two quantities are equal Re: Which is greater?   [#permalink] 10 Dec 2017, 04:22
Display posts from previous: Sort by

Which is greater?  Question banks Downloads My Bookmarks Reviews Important topics  Powered by phpBB © phpBB Group Kindly note that the GRE® test is a registered trademark of the Educational Testing Service®, and this site has neither been reviewed nor endorsed by ETS®.