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# When the positive integer x is divided by 6, the remainder i

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Joined: 07 Jun 2014
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GRE 1: Q167 V156
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When the positive integer x is divided by 6, the remainder i [#permalink]  12 Aug 2018, 15:35
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Question Stats:

42% (01:01) correct 57% (01:12) wrong based on 7 sessions
When the positive integer x is divided by 6, the remainder is 4. Each of the following could also be an integer EXCEPT

(A) $$\frac{x}{2}$$
(B) $$\frac{x}{3}$$
(C) $$\frac{x}{7}$$
(D) $$\frac{x}{11}$$
(E) $$\frac{x}{17}$$
[Reveal] Spoiler: OA

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Sandy
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GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4857
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 105

Kudos [?]: 1776 [0], given: 397

Re: When the positive integer x is divided by 6, the remainder i [#permalink]  15 Aug 2018, 05:24
Expert's post
Explanation

When dealing with remainder questions on the GRE, the best thing to do is test a few real numbers:

Multiples of 6 are 0, 6, 12, 18, 24, 30, 36, etc.

Numbers with a remainder of 4 when divided by 6 are those 4 greater than the multiples of 6:

x could be 4, 10, 16, 22, 28, 34, 40, etc.

You could keep listing numbers, but this is probably enough to establish a pattern.

(A) $$\frac{x}{2}$$ → ALL of the listed x values are divisible by 2. Eliminate (A).

(B) $$\frac{x}{3}$$ → NONE of the listed x values are divisible by 3, but continue checking.

(C) $$\frac{x}{7}$$ → 28 is divisible by 7.

(D) $$\frac{x}{11}$$ → 22 is divisible by 11.

(E) $$\frac{x}{18}$$ → 34 is divisible by 17.

The question is “Each of the following could also be an integer EXCEPT.” Since four of the choices could be integers, (B) must be the answer.
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Sandy
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Re: When the positive integer x is divided by 6, the remainder i   [#permalink] 15 Aug 2018, 05:24
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