Carcass wrote:

What is the remainder when \(6^3\) id divided by 8?

(A) 5

(B) 3

(C) 2

(D) 1

(E) 0

6 = (2)(3)

So, 6³ = [(2)(3)]³

= [(2)(3)][(2)(3)][(2)(3)]

= (2)(2)

(2)(3)(3)(3)

= (2)(2)

(18)(3)

Aha! So, 6³ is a multiple of

18, which means the remainder will by 0, when 6³ is divided by

18Answer: E

Cheers,

Brent

_________________

Brent Hanneson – Creator of greenlighttestprep.com

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