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Re: What is the range of the se [#permalink]
25 Sep 2017, 05:18

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To compare fractions with different denominators, we have to find the MCM and then we just have to compare the numerators. So that we can find the maximum and minimum and compute the range. The MCM here is 24024. Then the fractions becomes \(\frac{16016}{24024},\frac{17472}{24024},\frac{15015}{24024},\frac{13728}{24024},\frac{16632}{24024}\). Thus, the range is computed as \(\frac{17472}{24024}-\frac{13728}{24024}=\frac{3744}{24024}=\frac{12}{77}\). Here we are!

Re: What is the range of the se [#permalink]
22 Aug 2018, 17:18

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Try to find the largest and the least。 It's better to compare a pair: 2/3＜8/11 （2*11 ＜3*8 ）； then the second pair: 8/11 ＞ 5/8 （64＞55）；the third pair: 8/11 ＞ 4/7 (56 ＞44）； the last pair:8/11 ＞ 9/13 (104＞99). So 8/11 is the largest. In the same way, we can find the least: 4/7. 8/11-4/7=56/77-44/77= 12/77.

Re: What is the range of the se [#permalink]
25 Aug 2018, 00:23

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IMO the easiest way to solve this is to just convert all of the numbers into decimals. I was already familiar with 2/3 (everyone should know this one!), 5/8 and 4/7. Took 10s to convert the other two. From there it was pretty easy to spot the greatest and smallest number. Then it's just a matter of subtracting the two fractions. All of this can be done within a minute.

greprepclubot

Re: What is the range of the se
[#permalink]
25 Aug 2018, 00:23