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# What is the product of the factors of twice the sum of the

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What is the product of the factors of twice the sum of the [#permalink]  18 Mar 2018, 06:32
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Question Stats:

75% (00:43) correct 25% (00:00) wrong based on 4 sessions
What is the product of the factors of twice the sum of the roots of the equation $$2x^2 - 4x - 6 = 0$$?

Drill 2
Question: 3
Page: 497

[Reveal] Spoiler: OA
8

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GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4810
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 118

Kudos [?]: 1897 [0], given: 397

Re: What is the product of the factors of twice the sum of the [#permalink]  18 Mar 2018, 06:55
Expert's post
Explanation

First, factor the quadratic: (2x + 2)(x – 3) = 0.

Next, solve for each solution (root). If 2x + 2 = 0, then x = –1. If x – 3 = 0, then x = 3.

The sum of the roots is 2, and twice their sum is 4.

The factors of 4 are 1, 2, 4, and the product of those factors is 8, the final answer.
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Re: What is the product of the factors of twice the sum of the [#permalink]  30 Mar 2018, 02:24
To simplify the equation further, 2 can be taken common so that factoring gets easy. Arthematic question with words instead of symbols is confusing!!
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Re: What is the product of the factors of twice the sum of the [#permalink]  30 Mar 2018, 20:02
What is the product of the factors of twice the sum of the roots of the equation 2x^2 - 4x - 6 = 0?

FIRST STEP : Find roots of the of the equation by the formula of roots of quadratic equation of the following equation.

SECOND STEP : After you find out the roots of equation, Which are coming 3 and -1. Find their sum.

THIRD STEP : SUM = 3+(-1) = 2. Multiply by 2 as it is written twice the sum. So you get 2*2= 4.

FOURTH STEP : Find factors of 4, which is 1,2,4.

FIFTH STEP : FIND THEIR PRODUCT AS = 1*2*4 =8
Re: What is the product of the factors of twice the sum of the   [#permalink] 30 Mar 2018, 20:02
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