We can re write as : \(\frac{1}{2^n} < \frac{1}{100}\)

Now to satisfy the equation \(\frac{1}{2^n}\) > 100 (Since greater the denominator the smaller the number)

So \(2^7\) = 128 which is greater than 100

Hence \(\frac{1}{2^n} < 0.01\) holds correct when the least value of n = 7
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