What is the least integer value of \(n\) such that \(\frac{1}{2^n} < 0.01\) ?

A. 7

B. 11

C. 50

D. 51

E. None of the above
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We can rewrite the equation as 1/2^(n) < 1/100, which is 2^(n) > 100. We may see 100 as (2*5)^2 = 2^2 * 5^2.
Thus 2^(n)/2^2 = 5^2 or 2^(n-2) = 25. We are looking for the least value of 2^(n-2) which is greater than 25. The least power of 2 greater than 25 is 2^5 = 32.
Therefore n-2 = 5 or n=7.
Answer is A.

Regards.
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