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# What is the area of triangle ABC shown above?

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What is the area of triangle ABC shown above? [#permalink]  01 Jun 2016, 16:48
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00:00

Question Stats:

77% (00:57) correct 22% (00:58) wrong based on 22 sessions
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#GREpracticequestion What is the area of triangle ABC shown above.jpg [ 11.18 KiB | Viewed 1114 times ]

What is the area of triangle ABC shown above?

A. 18

B. 20

C. $$12\sqrt{3}$$

D. $$18\sqrt{3}$$

E. 36

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Question: 7
Page: 101
[Reveal] Spoiler: OA

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Sandy
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Joined: 07 Jun 2014
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Re: What is the area of triangle ABC shown above? [#permalink]  01 Jun 2016, 16:52
Expert's post
Explanation

The triangle is a 30°-60°-90° triangle, so the ratio of the lengths of the legs is 1 to $$\sqrt{3}$$. Since the
length of the shorter leg, AB, is 6, it follows that the length of the longer leg, AC, is $$\frac{6}{3}$$. The area
of the triangle is therefore $$\frac{1}{2}6*6\sqrt{3}$$, or $$18\sqrt{3}$$.

The correct answer is Choice D.
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Re: What is the area of triangle ABC shown above? [#permalink]  05 Jul 2017, 20:00
sandy wrote:
Explanation

The triangle is a 30°-60°-90° triangle, so the ratio of the lengths of the legs is 1 to $$\sqrt{3}$$. Since the
length of the shorter leg, AB, is 6, it follows that the length of the longer leg, AC, is $$\frac{6}{3}$$. The area
of the triangle is therefore $$\frac{1}{2}6*6\sqrt{3}$$, or $$18\sqrt{3}$$.

The correct answer is Choice D.

How come 18\sqrt{3} will be equal to 18/3?
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Re: What is the area of triangle ABC shown above? [#permalink]  05 Jul 2017, 20:26
Hi
The choices mentioned are wrong..

I took 4 minutes and 40 seconds and could not get my head around the choices until I saw your solution which mentions that D is correct..

Correct the typos and please make sure that there are no typos at-least in the question part.

Thank you.
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Re: What is the area of triangle ABC shown above? [#permalink]  26 Jul 2017, 00:30
Doesn't D say 18/3 than 18/root 3? Please check the symbols - I picked A cause that was the closes to 18*root3
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Re: What is the area of triangle ABC shown above? [#permalink]  11 Feb 2019, 10:49
Expert's post
Sorry folks.
I have edited the original answer choices.

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com

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Re: What is the area of triangle ABC shown above? [#permalink]  28 May 2019, 10:17
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Im having trouble indentifying 6/3 for length AC. How are we getting that? Is it due to the enlargement ratio being 6. can someone please elaborate???

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Re: What is the area of triangle ABC shown above? [#permalink]  28 May 2019, 11:23
Expert's post
Attachment:

#GREpracticequestion What is the area of triangle ABC shown above.jpg [ 16.33 KiB | Viewed 444 times ]

Forget the explanations above.

The triangle is a $$30:60:90$$ triangle

Now it adheres to the standard $$x:x \sqrt{3}: 2x$$

Now the opposite side to the smallest angle - 30 - is 6.

So the standard above becomes $$6 : 6 \sqrt{3}: 12$$ because $$x = 6$$

So the area is $$\frac{b*h}{2} = \frac{6 \sqrt{3} * 6}{2} = \frac{36 \sqrt{3} }{2} = 18 \sqrt{3}$$

Regards
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Re: What is the area of triangle ABC shown above?   [#permalink] 28 May 2019, 11:23
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